This chapter is currently out of syllabus
1
JEE Main 2022 (Online) 29th June Morning Shift
+4
-1
Out of Syllabus Only 2% of the optical source frequency is the available channel bandwidth for an optical communicating system operating at 1000 nm. If an audio signal requires a bandwidth of 8 kHz, how many channels can be accommodated for transmission :

A
375 $$\times$$ 107
B
75 $$\times$$ 107
C
375 $$\times$$ 108
D
75 $$\times$$ 109
2
JEE Main 2022 (Online) 28th June Evening Shift
+4
-1
Out of Syllabus Amplitude modulated wave is represented by $${V_{AM}} = 10\,[1 + 0.4\cos (2\pi \times {10^4}t)]\cos (2\pi \times {10^7}t)$$. The total bandwidth of the amplitude modulated wave is :

A
10 kHz
B
20 MHz
C
20 kHz
D
10 MHz
3
JEE Main 2022 (Online) 28th June Morning Shift
+4
-1
Out of Syllabus Match List-I with List-II

List-I List-II
(A) Television signal (I) 03 KHz
(B) Radio signal (II) 20 KHz
(C) High Quality Music (III) 02 MHz
(D) Human speech (IV) 06 MHz

A
A-I, B-II, C-III, D-IV
B
A-IV, B-III, C-I, D-II
C
A-IV, B-III, C-II, D-I
D
A-I, B-II, C-IV, D-III
4
JEE Main 2022 (Online) 27th June Evening Shift
+4
-1
Out of Syllabus We do not transmit low frequency signal to long distances because-

(a) The size of the antenna should be comparable to signal wavelength which is unreal solution for a signal of longer wavelength.

(b) Effective power radiated by a long wavelength baseband signal would be high.

(c) We want to avoid mixing up signals transmitted by different transmitter simultaneously.

(d) Low frequency signal can be sent to long distances by superimposing with a high frequency wave as well.

Therefore, the most suitable option will be :

A
All statements are true
B
(a), (b) and (c) are true only
C
(a), (c) and (d) are true only
D
(b), (c) and (d) are true only
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