1
JEE Main 2018 (Offline)
+4
-1
In a collinear collision, a particle with an initial speed v0 strikes a stationary particle of the same mass. If the final total kinetic energy is 50% greater than the original kinetic energy, the magnitude of the relative velocity between the two particles, after collision, is :
A
$${{{v_0}} \over {\sqrt 2 }}$$
B
$${{v_0}} \over 4$$
C
$$\sqrt 2 {v_0}$$
D
$${{v_0}} \over 2$$
2
JEE Main 2018 (Offline)
+4
-1
The mass of a hydrogen molecule is 3.32 $$\times$$ 10-27 kg. If 1023 hydrogen molecules strike, per second, a fixed wall of area 2 cm2 at an angle of 45o to the normal, and rebound elastically with a speed of 103 m/s, then the pressure on the wall is nearly:
A
2.35 $$\times$$ 103 N m-2
B
4.70 $$\times$$ 103 N m-2
C
2.35 $$\times$$ 102 N m-2
D
4.70 $$\times$$ 102 N m-2
3
JEE Main 2018 (Online) 15th April Evening Slot
+4
-1
A proton of mass m collides elastically with a particle of unknown mass at rest. After the collision, the proton and the unknown particle are seen moving at an angle of 90o with respect to each other. The mass of unknown particle is :
A
$${m \over 2}$$
B
m
C
$${m \over {\sqrt 3 }}$$
D
2 m
4
JEE Main 2017 (Online) 9th April Morning Slot
+4
-1
Two particles A and B of equal mass M are moving with the same speed $$\upsilon$$ as shown in the figure. They collide completely inelastically and move as a single particle C. The angle $$\theta$$ that the path of C makes with the X-axis is given by :

A
tan $$\theta$$ = $${{\sqrt 3 + \sqrt 2 } \over {1 - \sqrt 2 }}$$
B
tan $$\theta$$ = $${{\sqrt 3 - \sqrt 2 } \over {1 - \sqrt 2 }}$$
C
tan $$\theta$$ = $${{1 - \sqrt 2 } \over {\sqrt 2 \left( {1 + \sqrt 3 } \right)}}$$
D
tan $$\theta$$ = $${{1 - \sqrt 3 } \over {1 + \sqrt 2 }}$$
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