JEE Main 2020 (Online) 8th January Evening Slot | Rotational Motion Question 94 | Physics

JEE Main 2020 (Online) 8th January Evening Slot

MCQ (Single Correct Answer)

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As shown in figure, when a spherical cavity (centered at O) of radius 1 is cut out of a uniform sphere of radius R (centered at C), the centre of mass of remaining (shaded) part of sphere is at G, i.e, on the surface of the cavity. R can be detemined by the equation : JEE Main 2020 (Online) 8th January Evening Slot Physics - Rotational Motion Question 96 English

JEE Main 2020 (Online) 8th January Evening Slot Physics - Rotational Motion Question 96 English

(R² + R – 1) (2 – R) = 1

(R² – R – 1) (2 – R) = 1

(R² – R + 1) (2 – R) = 1

(R² + R + 1) (2 – R) = 1

JEE Main 2020 (Online) 8th January Evening Slot

MCQ (Single Correct Answer)

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A uniform sphere of mass 500 g rolls without slipping on a plane horizontal surface with its centre moving at a speed of 5.00 cm/s. Its kinetic energy is :

8.75 × 10^–3 J

1.13 × 10^–3 J

8.75 × 10^–4 J

6.25 × 10^–4 J

JEE Main 2020 (Online) 8th January Morning Slot

MCQ (Single Correct Answer)

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Consider a uniform rod of mass M = 4m and length $$\ell $$ pivoted about its centre. A mass m moving with velocity v making angle $$\theta = {\pi \over 4}$$ to the rod's long axis collides with one end of the rod and sticks to it. The angular speed of the rod-mass system just after the collision is :

$${{3\sqrt 2 } \over 7}{v \over \ell }$$

$${3 \over 7}{v \over \ell }$$

$${3 \over {7\sqrt 2 }}{v \over \ell }$$

$${4 \over 7}{v \over \ell }$$

JEE Main 2020 (Online) 8th January Morning Slot

MCQ (Single Correct Answer)

-1

The coordinates of centre of mass of a uniform flag shaped lamina (thin flat plate) of mass 4kg. (The coordinates of the same are shown in figure) are : JEE Main 2020 (Online) 8th January Morning Slot Physics - Rotational Motion Question 98 English