1
JEE Main 2020 (Online) 8th January Evening Slot
+4
-1
As shown in figure, when a spherical cavity (centered at O) of radius 1 is cut out of a uniform sphere of radius R (centered at C), the centre of mass of remaining (shaded) part of sphere is at G, i.e, on the surface of the cavity. R can be detemined by the equation :
A
(R2 + R – 1) (2 – R) = 1
B
(R2 – R – 1) (2 – R) = 1
C
(R2 – R + 1) (2 – R) = 1
D
(R2 + R + 1) (2 – R) = 1
2
JEE Main 2020 (Online) 8th January Evening Slot
+4
-1
A particle of mass m is dropped from a height h above the ground. At the same time another particle of the same mass is thrown vertically upwards from the ground with a speed of $$\sqrt {2gh}$$. If they collide head-on completely inelastically, the time taken for the combined mass to reach the ground, in units of $$\sqrt {{h \over g}}$$ is :
A
$$\sqrt {{1 \over 2}}$$
B
$${1 \over 2}$$
C
$$\sqrt {{3 \over 2}}$$
D
$$\sqrt {{3 \over 4}}$$
3
JEE Main 2020 (Online) 8th January Morning Slot
+4
-1
The coordinates of centre of mass of a uniform flag shaped lamina (thin flat plate) of mass 4kg. (The coordinates of the same are shown in figure) are :
A
(0.75m, 1.75m)
B
(1m, 1.75m)
C
(0.75m, 0.75m)
D
(1.25m, 1.50m)
4
JEE Main 2020 (Online) 7th January Morning Slot
+4
-1
Three point particles of masses 1.0 kg, 1.5 kg and 2.5 kg are placed at three corners of a right angle triangle of sides 4.0 cm, 3.0 cm and 5.0 cm as shown in the figure. The center of mass of the system is at a point:
A
2.0 cm right and 0.9 cm above 1 kg mass
B
0.9 cm right and 2.0 cm above 1 kg mass
C
0.6 cm right and 2.0 cm above 1 kg mass
D
1.5 cm right and 1.2 cm above 1 kg mass
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