JEE Main 2019 (Online) 10th April Morning Slot | Communication Systems Question 75 | Physics

A message signal of frequency 100 MHz and peak voltage 100 V is used to execute amplitude modulation on a carrier wave of frequency 300 GHz and peak voltage 400 V. The modulation index and difference between the two side band frequencies are :

0.25; 1 × 10⁸ Hz

4; 2 × 10⁸ Hz

4; 1 × 10⁸ Hz

0.25; 2 × 10⁸ Hz

JEE Main 2019 (Online) 10th April Morning Slot

MCQ (Single Correct Answer)

-1

Out of Syllabus

Given below in the the left column are different modes of communication using the kinds of waves given the right column.

A	Optical Fibre communication	P	Ultrasound
B	Radar	Q	Infrared Light
C	Sonar	R	Microwaves
D	Mobile Phones	S	Radio Waves

A-Q, B-S, C-R, D-P

A-Q, B-S, C-P, D-R

A-S, B-Q, C-R, D-P

A-R, B-P, C-S, D-Q

JEE Main 2019 (Online) 9th April Evening Slot

MCQ (Single Correct Answer)

-1

Out of Syllabus

The physical sizes of the transmitter and receiver antenna in a communication system are :-

proportional to carrier frequency

inversely proportional to carrier frequency

inversely proportional to modulation frequency

independent of both carrier and modulation frequency

JEE Main 2019 (Online) 9th April Morning Slot

MCQ (Single Correct Answer)

-1

Out of Syllabus

A signal Acoswt is transmitted using v₀ sin $$\omega $$₀t as carrier wave. The correct amplitude modulated (AM) signal is

v₀ sin $$\omega $$₀t + Acos$$\omega $$t

(v₀ + A)cos$$\omega $$t sin$$\omega $$₀ t

v₀ sin[$$\omega $$₀ (1+ 0.01Asin$$\omega $$t)t]

$${v_0}\sin {\omega _0}t + {{\rm A} \over 2}\sin ({\omega _0} - \omega )t + {A \over 2}\sin ({\omega _0} + \omega )t$$

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