As diodes D₁ and D₂ are in forward bias, so they acted as negligible resistances

$$\Rightarrow$$ Input voltage become zero


$$\Rightarrow$$ Input current is zero

$$\Rightarrow$$ Output current is zero

$$\Rightarrow$$ V₀ = 5 volt

$$i = {{10V} \over {5k\Omega }}$$ = 2mA

$$I = {{14V} \over {1k\Omega }}$$ = 14 mA

$$\therefore$$ I_z = 12 mA

$$\therefore$$ P = I_zV_z = 120 mW

V = 12 kV

Number of revolution = n

$$n[2 \times {q_P} \times V] = {1 \over 2}{m_P} \times v_P^2$$

$$n[2 \times 1.6 \times {10^{ - 19}} \times 12 \times {10^3}]$$

$$ = {1 \over 2} \times 1.67 \times {10^{ - 27}} \times {\left[ {{{3 \times {{10}^8}} \over 6}} \right]^2}$$

n(38.4 $$\times$$ 10^$$-$$16) = 0.2087 $$\times$$ 10^$$-$$11

n = 543.4

$${n_e}{n_h} = {n_i}^2$$

$${n_e} = {{{n_i}^2} \over {{n_h}}} = {{{{(1.5 \times {{10}^{16}})}^2}} \over {4.5 \times {{10}^{22}}}}$$

$$ = {{1.5 \times 1.5 \times {{10}^{32}}} \over {4.5 \times {{10}^{22}}}}$$

$$ = 5 \times {10^9}$$/m³