1
JEE Main 2022 (Online) 26th July Evening Shift
Numerical
+4
-1
Out of Syllabus
Change Language

A potentiometer wire of length $$300 \mathrm{~cm}$$ is connected in series with a resistance 780 $$\Omega$$ and a standard cell of emf $$4 \mathrm{V}$$. A constant current flows through potentiometer wire. The length of the null point for cell of emf $$20\, \mathrm{mV}$$ is found to be $$60 \mathrm{~cm}$$. The resistance of the potentiometer wire is ____________ $$\Omega$$.

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2
JEE Main 2022 (Online) 26th July Morning Shift
Numerical
+4
-1
Change Language

Resistances are connected in a meter bridge circuit as shown in the figure. The balancing length $$l_{1}$$ is $$40 \mathrm{~cm}$$. Now an unknown resistance $$x$$ is connected in series with $$\mathrm{P}$$ and new balancing length is found to be $$80 \mathrm{~cm}$$ measured from the same end. Then the value of $$x$$ will be ____________ $$\Omega$$.

JEE Main 2022 (Online) 26th July Morning Shift Physics - Current Electricity Question 100 English

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3
JEE Main 2022 (Online) 25th July Evening Shift
Numerical
+4
-1
Out of Syllabus
Change Language

In a potentiometer arrangement, a cell of emf 1.20 V gives a balance point at 36 cm length of wire. This cell is now replaced by another cell of emf 1.80 V. The difference in balancing length of potentiometer wire in above conditions will be ___________ cm.

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4
JEE Main 2022 (Online) 25th July Morning Shift
Numerical
+4
-1
Change Language

In the given figure, the value of Vo will be _____________ V.

JEE Main 2022 (Online) 25th July Morning Shift Physics - Current Electricity Question 105 English

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