A particle of mass 500 gm is moving in a straight line with velocity v = b x^{5/2}. The work done by the net force during its displacement from x = 0 to x = 4 m is : (Take b = 0.25 m^{$$-$$3/2} s^{$$-$$1}).

In the arrangement shown in figure a_{1}, a_{2}, a_{3} and a_{4} are the accelerations of masses m_{1}, m_{2}, m_{3} and m_{4} respectively. Which of the following relation is true for this arrangement?

Arrange the four graphs in descending order of total work done; where W_{1}, W_{2}, W_{3} and W_{4} are the work done corresponding to figure a, b, c and d respectively.

A particle experiences a variable force $$\overrightarrow F = \left( {4x\widehat i + 3{y^2}\widehat j} \right)$$ in a horizontal x-y plane. Assume distance in meters and force is newton. If the particle moves from point (1, 2) to point (2, 3) in the x-y plane, then Kinetic Energy changes by :