NEW
New Website Launch
Experience the best way to solve previous year questions with mock tests (very detailed analysis), bookmark your favourite questions, practice etc...
1

IIT-JEE 1980

Two circles $${x^2} + {y^2} = 6$$ and $${x^2} + {y^2} - 6x + 8 = 0$$ are given. Then the equation of the circle through their points of intersection and the point (1, 1) is
A
$${x^2} + {y^2} - 6x + 4 = 0$$
B
$${x^2} + {y^2} - 3x + 1 = 0$$
C
$${x^2} + {y^2} - 4y + 2 = 0$$
D
none of these
2

IIT-JEE 1980

A square is inscribed in the circle $${x^2} + {y^2} - 2x + 4y + 3 = 0$$. Its sides are parallel to the coordinate axes. The one vertex of the square is
A
$$\left( {1 + \sqrt {2,} - 2} \right)$$
B
$$\,\left( {1 - \sqrt {2}, - 2} \right)$$
C
$$\,\,\left( {1, - 2 + \sqrt 2 } \right)$$
D
none of these

Joint Entrance Examination

JEE Main JEE Advanced WB JEE