1
JEE Advanced 2024 Paper 2 Online
MCQ (Single Correct Answer)
+3
-1
Let $S=\left\{(x, y) \in \mathbb{R} \times \mathbb{R}: x \geq 0, y \geq 0, y^2 \leq 4 x, y^2 \leq 12-2 x\right.$ and $\left.3 y+\sqrt{8} x \leq 5 \sqrt{8}\right\}$. If the area of the region $S$ is $\alpha \sqrt{2}$, then $\alpha$ is equal to
2
JEE Advanced 2021 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
The area of the region
$$\left\{ {\matrix{ {(x,y):0 \le x \le {9 \over 4},} & {0 \le y \le 1,} & {x \ge 3y,} & {x + y \ge 2} \cr } } \right\}$$ is
$$\left\{ {\matrix{ {(x,y):0 \le x \le {9 \over 4},} & {0 \le y \le 1,} & {x \ge 3y,} & {x + y \ge 2} \cr } } \right\}$$ is
3
JEE Advanced 2020 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
Let the functions f : R $$ \to $$ R and g : R $$ \to $$ R be defined by
f(x) = ex $$-$$ 1 $$-$$ e$$-$$|x $$-$$ 1|
and g(x) = $${1 \over 2}$$(ex $$-$$ 1 + e1 $$-$$ x).
The the area of the region in the first quadrant bounded by the curves y = f(x), y = g(x) and x = 0 is
f(x) = ex $$-$$ 1 $$-$$ e$$-$$|x $$-$$ 1|
and g(x) = $${1 \over 2}$$(ex $$-$$ 1 + e1 $$-$$ x).
The the area of the region in the first quadrant bounded by the curves y = f(x), y = g(x) and x = 0 is
4
JEE Advanced 2019 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
The area of the region
{(x, y) : xy $$ \le $$ 8, 1 $$ \le $$ y $$ \le $$ x2} is
{(x, y) : xy $$ \le $$ 8, 1 $$ \le $$ y $$ \le $$ x2} is
Questions Asked from Application of Integration (MCQ (Single Correct Answer))
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