Alcohols, Phenols and Ethers · Chemistry · JEE Advanced
MCQ (More than One Correct Answer)
Reaction of iso-propylbenzene with $\mathrm{O}_2$ followed by the treatment with $\mathrm{H}_3 \mathrm{O}^{+}$forms phenol and a by-product $\mathbf{P}$. Reaction of $\mathbf{P}$ with 3 equivalents of $\mathrm{Cl}_2$ gives compound $\mathbf{Q}$. Treatment of $\mathbf{Q}$ with $\mathrm{Ca}(\mathrm{OH})_2$ produces compound $\mathbf{R}$ and calcium salt $\mathbf{S}$.
The correct statement(s) regarding $\mathbf{P}, \mathbf{Q}, \mathbf{R}$ and $\mathbf{S}$ is(are)



The observed pattern of electrophilic substitution can be explained by
In the following reaction, the product/products formed is/are
The major product(s) of the following reaction is(are)
In the reaction
The intermediate(s) is(are)
MCQ (Single Correct Answer)

The correct statement about $\mathbf{S}$ is :

Match the reaction in LIST-I with one or more products in LIST-II and choose the correct option.
For the identification of $$\beta$$-naphthol using dye test, it is necessary to use
The acidic hydrolysis of ether (X) shown below is fastest when
Match the chemical conversions in List I with the appropriate reagents in List II and select the correct answer using the code given below the lists :
The compound that does NOT liberate CO2, on treatment with aqueous sodium bicarbonate solution, is
Match the reactions in Column I with appropriate types of steps/reactive intermediate involved in these reactions as given in Column II :
Column I | Column II | ||
---|---|---|---|
(A) | ![]() |
(P) | Nucleophilic substitution |
(B) | ![]() |
(Q) | Electrophilic substitution |
(C) | ![]() |
(R) | Dehydration |
(D) | ![]() |
(S) | Nucleophilic |
(T) | Carbanion |
In the reaction
the products are :
Compound H is formed by the reaction of
The structure of compound I is :
The structures of compound J, K and L, respectively, are:
Numerical
The number of hydroxyl group(s) in Q is ___________.
The number of resonance structure for N is _________.