If the two circles $${(x - 1)^2} + {(y - 3)^2} = {r^2}$$ and $${x^2} + {y^2} - 8x + 2y + 8 = 0$$ intersect in two distinct points, then
A
2 < r < 8
B
r < 2
C
r = 2
D
r > 2
2
IIT-JEE 1988
MCQ (Single Correct Answer)
If a circle passes through the point (a, b) and cuts the circle $${x^2}\, + \,{y^2}\, = \,{k^2}$$ orthogonally, then the equation of the locus of its centre is
The locus of the mid-point of a chord of the circle $${x^2} + {y^2} = 4$$ which subtends a right angle at the origin is
A
x + y = 2
B
$${x^2} + {y^2} = 1$$
C
$${x^2} + {y^2} = 2$$
D
$$x + y $$=1
4
IIT-JEE 1983
MCQ (Single Correct Answer)
The equation of the circle passing through (1, 1) and the points of intersection of $${x^2} + {y^2} + 13x - 3y = 0$$ and $$2{x^2} + 2{y^2} + 4x - 7y - 25 = 0$$ is
A
$$4{x^2} + 4{y^2} - 30x - 10y - 25 = 0$$
B
$$4{x^2} + 4{y^2} + 30x - 13y - 25 = 0$$
C
$$4{x^2} + 4{y^2} - 17x - 10y + 25 = 0$$
D
none of these
Questions Asked from Circle
On those following papers in MCQ (Single Correct Answer)
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