Let the straight line $y=2 x$ touch a circle with center $(0, \alpha), \alpha>0$, and radius $r$ at a point $A_1$. Let $B_1$ be the point on the circle such that the line segment $A_1 B_1$ is a diameter of the circle. Let $\alpha+r=5+\sqrt{5}$.

Match each entry in List-I to the correct entry in List-II.

List-I	List-II
(P) $\alpha$ equals	(1) $(-2, 4)$
(Q) $r$ equals	(2) $\sqrt{5}$
(R) $A_1$ equals	(3) $(-2, 6)$
(S) $B_1$ equals	(4) $5$
	(5) $(2, 4)$

The correct option is

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