1
IIT-JEE 1993
+1
-0.25
The locus of the centre of a circle, which touches externally the circle $${x^2} + {y^2} - 6x - 6y + 14 = 0$$ and also touches the y-axis, is given by the equation:
A
$${x^2} - 6x - 10y + 14 = 0$$
B
$${x^2} - 10x - 6y + 14 = 0$$
C
$${y^2} - 6x - 10y + 14 = 0$$
D
$${y^2} - 10x - 6y + 14 = 0$$
2
IIT-JEE 1992
+2
-0.5
The centre of a circle passing through the points (0, 0), (1, 0) and touching the circle $${x^2} + {y^2} = 9$$is
A
$$\left( {{3 \over 2},{1 \over 2}} \right)\,$$
B
$$\left( {{1 \over 2},{3 \over 2}} \right)\,$$
C
$$\left( {{1 \over 2},{1 \over 2}} \right)\,$$
D
$$\left( {{1 \over 2}, - {2^{{1 \over 2}}}} \right)\,$$
3
IIT-JEE 1989
+2
-0.5
If the two circles $${(x - 1)^2} + {(y - 3)^2} = {r^2}$$ and $${x^2} + {y^2} - 8x + 2y + 8 = 0$$ intersect in two distinct points, then
A
2 < r < 8
B
r < 2
C
r = 2
D
r > 2
4
IIT-JEE 1989
+2
-0.5
The lines 2x - 3y = 5 and 3x - 4y = 7 are diameters of a circle of area 154 sq. units. Then the equation of this circle is
A
$${x^2} + {y^2} + 2x - 2y = 62$$
B
$${x^2} + {y^2} + 2x - 2y = 47$$
C
$${x^2} + {y^2} - 2x + 2y = 47$$
D
$${x^2} + {y^2} - 2x + 2y = 62$$c
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