Statistics · Mathematics · JEE Advanced

Consider the following frequency distribution:

Value	4	5	8	9	6	12	11
Frequency	5	$f_1$	$f_2$	2	1	1	3

Suppose that the sum of the frequencies is 19 and the median of this frequency distribution is 6.

For the given frequency distribution, let $\alpha$ denote the mean deviation about the mean, $\beta$ denote the mean deviation about the median, and $\sigma^2$ denote the variance.

Match each entry in List-I to the correct entry in List-II and choose the correct option.

List – I	List – II
(P) 7 f1 + 9 f2 is equal to	(1) 146
(Q) 19 α is equal to	(2) 47
(R) 19 β is equal to	(3) 48
(S) 19 σ2 is equal to	(4) 145
	(5) 55

Consider the given data with frequency distribution

$$ \begin{array}{ccccccc} x_i & 3 & 8 & 11 & 10 & 5 & 4 \\ f_i & 5 & 2 & 3 & 2 & 4 & 4 \end{array} $$

Match each entry in List-I to the correct entries in List-II.

List - I	List - II
(P) The mean of the above data is	(1) 2.5
(Q) The median of the above data is	(2) 5
(R) The mean deviation about the mean of the above data is	(3) 6
(S) The mean deviation about the median of the above data is	(4) 2.7
	(5) 2.4

The correct option is: