IIT-JEE 2004 Screening | Conic Sections Question 81 | Mathematics

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IIT-JEE 2004 Screening

MCQ (Single Correct Answer)

-0.5

The angle between the tangents drawn from the point $$(1, 4)$$ to the parabola $${y^2} = 4x$$ is

$$\pi /6$$

$$\pi /4$$

$$\pi /3$$

$$\pi /2$$

IIT-JEE 2004 Screening

MCQ (Single Correct Answer)

-0.5

If tangents are drawn to the ellipse $${x^2} + 2{y^2} = 2,$$ then the locus of the mid-point of the intercept made by the tangents between the coordinate axes is

$${1 \over {2{x^2}}} + {1 \over {4{y^2}}} = 1$$

$${1 \over {4{x^2}}} + {1 \over {2{y^2}}} = 1$$

$${{{x^2}} \over 2} + {{{y^2}} \over 4} = 1$$

$${{{x^2}} \over 4} + {{{y^2}} \over 2} = 1$$

IIT-JEE 2004 Screening

MCQ (Single Correct Answer)

-0.5

If the line $$62x + \sqrt 6 y = 2$$ touches the hyperbola $${x^2} - 2{y^2} = 4$$, then the point of contact is

$$\left( { - 2,\,\sqrt 6 } \right)$$

$$\left( { - 5,\,2\sqrt 6 } \right)$$

$$\left( {{1 \over 2},{1 \over {\sqrt 6 }}} \right)$$

$$\left( {4, - \,\sqrt 6 } \right)$$

IIT-JEE 2003 Screening

MCQ (Single Correct Answer)

-0.5

The area of the quadrilateral formed by the tangents at the end points of latus rectum to the ellipse $${{{x^2}} \over 9} + {{{y^2}} \over 5} = 1,$$ is

$$27/4$$ sq. units

$$9$$ sq. units

$$27/2$$ sq. units

$$27$$ sq. units

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