IIT-JEE 2003 Screening | Parabola Question 40 | Mathematics

IIT-JEE 2003 Screening

MCQ (Single Correct Answer)

-0.5

The focal chord to $${y^2} = 16x$$ is tangent to $${\left( {x - 6} \right)^2} + {y^2} = 2,$$ then the possible values of the slope of the chord, are

$$\left\{ { - 1,\,1} \right\}$$

$$\left\{ { - 2,\,2} \right\}$$

$$\left\{ { - 2,\,-1/2} \right\}$$

$$\left\{ { 2,\,-1/2} \right\}$$

IIT-JEE 2002 Screening

MCQ (Single Correct Answer)

-0.5

The equation of the common tangent to the curves $${y^2} = 8x$$ and $$xy = - 1$$ is

$$3y = 9x + 2$$

$$y = 2x + 1$$

$$2y = x + 8$$

$$y= x + 2$$

IIT-JEE 2002 Screening

MCQ (Single Correct Answer)

-0.5

The locus of the mid-point of the line segment joining the focus to a moving point on the parabola $${y^2} = 4ax$$ is another parabola with directrix

$$x = -a$$

$$x = -a/2$$

$$x = 0$$

$$x = a/2$$

IIT-JEE 2001 Screening

MCQ (Single Correct Answer)

-0.5

The equation of the directrix of the parabola $${y^2} + 4y + 4x + 2 = 0$$

$$x = - 1$$

$$x = 1$$

$$x = - 3/2$$

$$x = 3/2$$

JEE Advanced Subjects