The locus of the orthocentre of the triangle formed by the lines

$$(1 + p)x - py + p(1 + p) = 0, $$

$$(1 + q)x - qy + q(1 + q) = 0$$

and $$y = 0$$, where $$p \ne q$$, is :

STATEMENT - 1 : The curve $$y=\frac{-x^{2}}{2}+x+1$$ is symmetric with respect to the line $$x=1$$.

STATEMENT - 2 : A parabola is symmetric about its axis.

The tangent to the curve $$y=e^x$$ drawn at the point ($$c,e^c$$) intersects the line joining the points ($$c-1,e^{c-1}$$) and ($$c+1,e^{c+1}$$)