1

### IIT-JEE 2005 Screening

Tangent to the curve $$y = {x^2} + 6$$ at a point $$(1, 7)$$ touches the circle $${x^2} + {y^2} + 16x + 12y + c = 0$$ at a point $$Q$$. Then the coordinates of $$Q$$ are
A
$$(-6, -11)$$
B
$$(-9, -13)$$
C
$$(-10, -15)$$
D
$$(-6, -7)$$
2

### IIT-JEE 2005 Screening

The minimum area of triangle formed by the tangent to the $${{{x^2}} \over {{a^2}}} + {{{y^2}} \over {{b^2}}} = 1$$ and coordinate axes is
A
$$ab$$ sq. units
B
$${{{{a^2} + {b^2}} \over 2}}$$ sq. units
C
$${{{{\left( {a + b} \right)}^2}} \over 2}$$ sq. units
D
$${{{a^2} + ab + {b^2}} \over 3}$$ sq. units
3

### IIT-JEE 2004 Screening

If the line $$62x + \sqrt 6 y = 2$$ touches the hyperbola $${x^2} - 2{y^2} = 4$$, then the point of contact is
A
$$\left( { - 2,\,\sqrt 6 } \right)$$
B
$$\left( { - 5,\,2\sqrt 6 } \right)$$
C
$$\left( {{1 \over 2},{1 \over {\sqrt 6 }}} \right)$$
D
$$\left( {4, - \,\sqrt 6 } \right)$$
4

### IIT-JEE 2004 Screening

If tangents are drawn to the ellipse $${x^2} + 2{y^2} = 2,$$ then the locus of the mid-point of the intercept made by the tangents between the coordinate axes is
A
$${1 \over {2{x^2}}} + {1 \over {4{y^2}}} = 1$$
B
$${1 \over {4{x^2}}} + {1 \over {2{y^2}}} = 1$$
C
$${{{x^2}} \over 2} + {{{y^2}} \over 4} = 1$$
D
$${{{x^2}} \over 4} + {{{y^2}} \over 2} = 1$$

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