IIT-JEE 2012 Paper 2 Offline | Circle Question 19 | Mathematics

IIT-JEE 2012 Paper 2 Offline

MCQ (Single Correct Answer)

-1

A tangent PT is drawn to the circle $${x^2}\, + {y^2} = 4$$ at the point P $$\left( {\sqrt 3 ,1} \right)$$. A straight line L, perpendicular to PT is a tangent to the circle $${(x - 3)^2}$$ + $${y^2}$$ = 1

A common tangent of the two circles is

x = 4

y = 2

$${x + \sqrt 3 \,y = 4}$$

$${x +2 \sqrt 2 \,y = 6}$$

IIT-JEE 2012 Paper 1 Offline

MCQ (Single Correct Answer)

-1

The locus of the mid-point of the chord of contact of tangents drawn from points lying on the straight line 4x - 5y = 20 to the circle $${x^2}\, + \,{y^2} = 9$$ is

$$20\,({x^2}\, + \,{y^2}) - \,\,36x\,\, + \,\,45y = 0$$

$$20\,({x^2}\, + \,{y^2}) + \,\,36x\,\, - \,\,45y = 0$$

$$36\,({x^2}\, + \,{y^2}) - \,\,20x\,\, + \,\,45y = 0$$

$$36\,({x^2}\, + \,{y^2}) + \,\,20x\,\, - \,\,45y = 0$$

IIT-JEE 2011 Paper 2 Offline

MCQ (Single Correct Answer)

-0.5

The circle passing through the point (-1, 0) and touching the y-axis at (0, 2) also passes through the point.

$$\left( { - {3 \over 0},0} \right)$$

$$\left( { - {5 \over 2},2} \right)$$

$$\left( { - {3 \over 0},\,{5 \over 2}} \right)$$

(- 4, 0)

IIT-JEE 2009 Paper 1 Offline

MCQ (Single Correct Answer)

-1

Tangents drawn from the point P (1, 8) to the circle
$${x^2}\, + \,{y^2}\, - \,6x\, - 4y\, - 11 = 0$$
touch the circle at the points A and B. The equation of the cirumcircle of the triangle PAB is

$${x^2}\, + \,{y^2}\, + \,4x\,\, - 6y\, + 19 = 0$$

$${x^2}\, + \,{y^2}\, - \,4x\,\, - 10y\, + 19 = 0$$

$${x^2}\, + \,{y^2}\, - \,2x\,\, + 6y\, - 29 = 0$$

$${x^2}\, + \,{y^2}\, - \,6x\,\, - 4y\, + 19 = 0$$

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