1
GATE ECE 2011
MCQ (Single Correct Answer)
+2
-0.6
The input-output transfer function of a plant is h(s)=$${{100} \over {s{{\left( {s + 10} \right)}^2}}}$$. The plant is placed in a unity negative feedback configuration as shown in the figure below. GATE ECE 2011 Control Systems - Frequency Response Analysis Question 29 English The signal flow graph that DOES NOT model the plant transfer function H(s) is
A
GATE ECE 2011 Control Systems - Frequency Response Analysis Question 29 English Option 1
B
GATE ECE 2011 Control Systems - Frequency Response Analysis Question 29 English Option 2
C
GATE ECE 2011 Control Systems - Frequency Response Analysis Question 29 English Option 3
D
GATE ECE 2011 Control Systems - Frequency Response Analysis Question 29 English Option 4
2
GATE ECE 2009
MCQ (Single Correct Answer)
+2
-0.6
The Nyquist plot of a stable transfer function G(s) is shown in the figure. We are interested in the stability of the closed loop system in the feedback configuration shown. GATE ECE 2009 Control Systems - Frequency Response Analysis Question 30 English 1 GATE ECE 2009 Control Systems - Frequency Response Analysis Question 30 English 2 The gain and phase margins of G(s) for closed loop stability are
A
6 dB and $$180^\circ $$
B
3 dB and $$180^\circ $$
C
6 dB and $$90^\circ $$
D
3 dB and $$90^\circ $$
3
GATE ECE 2009
MCQ (Single Correct Answer)
+2
-0.6
The Nyquist plot of a stable transfer function G(s) is shown in the figure. We are interested in the stability of the closed loop system in the feedback configuration shown. GATE ECE 2009 Control Systems - Frequency Response Analysis Question 31 English 1 GATE ECE 2009 Control Systems - Frequency Response Analysis Question 31 English 2 Which of the foloowing statements is true?
A
G(s) is is an all-pass filter.
B
G(s) has a zero in the right-half of S-plane.
C
G(s) is the impedance of a passive network.
D
G(s) is marginally stable.
4
GATE ECE 2008
MCQ (Single Correct Answer)
+2
-0.6
The impulse response h(t) of a linear time invariant system is given by h(t) = $${e^{ - 2t}}u(t),$$ where u(t) denotes the unit step function.

The output of this system to the sinusoidal input x(t) = 2cos(t) for all time 't' is

A
$$0$$
B
$${2^{ - 0.25}}\cos \left( {2t - 0.125\pi } \right)$$
C
$${2^{ - 0.5}}\cos \left( {2t - 0.125\pi } \right)$$
D
$${2^{ - 0.5}}\cos \left( {2t - 0.25\pi } \right)$$
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