1
GATE ECE 2025
MCQ (Single Correct Answer)
+2
-0.67

Consider a system represented by the block diagram shown below. Which of the following signal flow graphs represent(s) this system? Choose the correct option(s).

GATE ECE 2025 Control Systems - Signal Flow Graph and Block Diagram Question 1 English
A
GATE ECE 2025 Control Systems - Signal Flow Graph and Block Diagram Question 1 English Option 1
B
GATE ECE 2025 Control Systems - Signal Flow Graph and Block Diagram Question 1 English Option 2
C
GATE ECE 2025 Control Systems - Signal Flow Graph and Block Diagram Question 1 English Option 3
D
GATE ECE 2025 Control Systems - Signal Flow Graph and Block Diagram Question 1 English Option 4
2
GATE ECE 2023
MCQ (Single Correct Answer)
+2
-0.67

In the following block diagram, R(s) and D(s) are two inputs. The output Y(s) is expressed as Y(s) = G$$_1$$(s)R(s) + G$$_2$$(s)D(s).

G$$_1$$(s) and G$$_2$$(s) are given by

GATE ECE 2023 Control Systems - Signal Flow Graph and Block Diagram Question 2 English

A
$${G_1}(s) = {{G(s)} \over {1 + G(s) + G(s)H(s)}}$$ and $${G_2}(s) = {{G(s)} \over {1 + G(s) + G(s)H(s)}}$$
B
$${G_1}(s) = {{G(s)} \over {1 + G(s) + H(s)}}$$ and $${G_2}(s) = {{G(s)} \over {1 + G(s) + H(s)}}$$
C
$${G_1}(s) = {{G(s)} \over {1 + G(s) + H(s)}}$$ and $${G_2}(s) = {{G(s)} \over {1 + G(s) + G(s)H(s)}}$$
D
$${G_1}(s) = {{G(s)} \over {1 + G(s) + G(s)H(s)}}$$ and $${G_2}(s) = {{G(s)} \over {1 + G(s) + H(s)}}$$
3
GATE ECE 2013
MCQ (Single Correct Answer)
+2
-0.6
The signal flow graph for a system is given below. The transfer function $$\frac{Y(s)}{U(s)}$$ for this system is GATE ECE 2013 Control Systems - Signal Flow Graph and Block Diagram Question 16 English
A
$$\frac{s+1}{5s^2+6s+2}$$
B
$$\frac{s+1}{s^2+6s+2}$$
C
$$\frac{s+1}{s^2+4s+2}$$
D
$$\frac{1}{5s^2+6s+2}$$
4
GATE ECE 2004
MCQ (Single Correct Answer)
+2
-0.6
Consider the signal flow graph shown in Figure. The gain $$\frac{x_5}{x_1}$$ is GATE ECE 2004 Control Systems - Signal Flow Graph and Block Diagram Question 5 English
A
$$\frac{1-\left(be\;+\;cf\;+\;dg\right)}{abcd}$$
B
$$\frac{bedg}{1-\left(be\;+\;cf\;+\;dg\right)}$$
C
$$\frac{abcd}{1-\left(be\;+\;cf\;+\;dg\right)\;+\;bedg}$$
D
$$\frac{1-\left(be\;+\;cf\;+\;dg\right)\;+\;bedg}{abcd}$$
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