GATE ECE 2008 | Frequency Response Analysis Question 31 | Control Systems

GATE ECE 2008

MCQ (Single Correct Answer)

-0.6

The magnitude of frequency response of an underdamped second order system is 5 at 0 rad/sec and peaks to $${{10} \over {\sqrt 3 }}$$ at 5 $$\sqrt 2 $$ rad/sec. The transfer function of the system is

$${{500} \over {{s^2} + 10s + 100}}$$

$${{375} \over {s2 + 5s + 75}}$$

$${{720} \over {s2 + 12s + 144}}$$

$${{1125} \over {s2 + 25s + 225}}$$

GATE ECE 2008

MCQ (Single Correct Answer)

-0.6

The impulse response h(t) of a linear time invariant system is given by h(t) = $${e^{ - 2t}}u(t),$$ where u(t) denotes the unit step function.

The output of this system to the sinusoidal input x(t) = 2cos(t) for all time 't' is

$$0$$

$${2^{ - 0.25}}\cos \left( {2t - 0.125\pi } \right)$$

$${2^{ - 0.5}}\cos \left( {2t - 0.125\pi } \right)$$

$${2^{ - 0.5}}\cos \left( {2t - 0.25\pi } \right)$$

GATE ECE 2007

MCQ (Single Correct Answer)

-0.6

The asymptotic Bode plot of a transfer function is shown in the figure. the transfer function G(s) corresponding to this bode plot is GATE ECE 2007 Control Systems - Frequency Response Analysis Question 24 English

GATE ECE 2007 Control Systems - Frequency Response Analysis Question 24 English

$${1 \over {\left( {s + 1} \right)\left( {s + 20} \right)}}$$

$${1 \over {s\left( {s + 1} \right)\left( {s + 20} \right)}}$$

$${{100} \over {s\left( {s + 1} \right)\left( {s + 20} \right)}}$$

$${{100} \over {s\left( {s + 1} \right)\left( {1 + 0.05s} \right)}}$$

GATE ECE 2006

MCQ (Single Correct Answer)

-0.6

Consider two transfer functions $${G_1}\left( s \right) = {1 \over {{s^2} + as + b}}$$ and $${G_2}\left( s \right) = {s \over {{s^2} + as + b}}.$$ The 3-dB bandwidths of their frequency responses are, respectively

$$\sqrt {{a^2} - 4b,} $$ $$\sqrt {{a^2} + 4b,} $$

$$\sqrt {{a^2} - 4b,} $$ $$\sqrt {{a^2} - 4b,} $$

$$\sqrt {{a^2} + 4b,} $$ $$\sqrt {{a^2} - 4b,} $$

$$\sqrt {{a^2} + 4b,} $$ $$\sqrt {{a^2} + 4b,} $$

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