GATE ECE 2020 | Combinational Circuits Question 8 | Digital Circuits

GATE ECE 2020

MCQ (Single Correct Answer)

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The figure below shows a multiplexer where $S_1$ and $S_0$ are the select lines, $I_0$ to $I_3$ are the input data lines, $E N$ is the enable line, and $F(P, Q, R)$ is the output. $F$ is

GATE ECE 2020 Digital Circuits - Combinational Circuits Question 2 English

$\bar{Q}+P R$

$P \bar{Q} R+\bar{P} Q$

$P+Q \bar{R}$

$P Q+\bar{Q} R$

GATE ECE 2017 Set 2

MCQ (Single Correct Answer)

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Consider the circuit shown in the figure. GATE ECE 2017 Set 2 Digital Circuits - Combinational Circuits Question 41 English

The Boolean expression F implemented by the circuit is

$$\overline X \,\overline Y \,\overline Z + XY + \,\overline Y \,Z$$

$$\overline X \,Y\,\overline Z + XZ + \,\overline Y \,Z$$

$$\overline X \,Y\,\overline Z + XY + \,\overline Y \,Z$$

$$\overline X \,\overline Y \,\overline Z + XZ + \,\overline Y \,Z$$

GATE ECE 2016 Set 2

MCQ (Single Correct Answer)

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A 4:1 multiplexer is to be used for generating the output carry of a full adder. A and B are the bits to be added while 𝐶in is the input carry and 𝐶out is the output carry. A and B are to be used as the select bits with A being the more significant select bit. GATE ECE 2016 Set 2 Digital Circuits - Combinational Circuits Question 42 English

GATE ECE 2016 Set 2 Digital Circuits - Combinational Circuits Question 42 English

Which one of the following statements correctly describes the choice of signals to be connected to the inputs $${I_0}$$, $${I_1}$$, $${I_2 }$$ and $${I_3}$$ so that the output is C$$_{out}$$?

$${I_0} = 0,{I_0} = {C_{in}},\,{I_{2\,}} = {C_{in}}\,and\,{I_3} = I$$

$${I_0} = 1,\,{I_1}\, = {C_{in}},\,{I_{2\,}} = {C_{in}}\,and\,{I_3} = I$$

$${I_0} = {C_{in}},\,\,{I_{1\,}} = 0,\,{I_{2\,}} = 1and\,{I_3} = \,{C_{in}}$$

$${I_0} = 0,{I_1} = {C_{in}},\,{I_{2\,}} = \,2and\,{I_3} = {C_{in}}\,$$

GATE ECE 2014 Set 2

MCQ (Single Correct Answer)

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In a half-subtractor circuit with X and Y as inputs, the Borrow (M) and Difference (N = X - Y) are given by

$$M = X \oplus Y,N = XY$$

$$M = XY,\,\,N = X \oplus Y$$

$$M = \overline X Y,\,\,N = X \oplus Y$$

$$M = X\overline Y ,\,\,\,N = \overline {X \oplus Y} $$