GATE ECE 2023 | Combinational Circuits Question 3 | Digital Circuits

GATE ECE 2023

MCQ (Single Correct Answer)

-0.33

In the circuit shown below, P and Q are the inputs. The logical function realized by the circuit shown below is

GATE ECE 2023 Digital Circuits - Combinational Circuits Question 3 English

Y = PQ

Y = P + Q

Y = $$\mathrm{\overline {PQ} }$$

Y = $$\mathrm{\overline {P+Q} }$$

GATE ECE 2022

MCQ (Single Correct Answer)

-0.33

Consider the 2-bit multiplexer (MUX) shown in the figure. For OUTPUT to be the XOR of C and D, the values for A₀, A₁, A₂ and A₃ are ___________.

GATE ECE 2022 Digital Circuits - Combinational Circuits Question 4 English

A₀ = 0, A₁ = 0, A₂ = 1, A₃ = 1

A₀ = 1, A₁ = 0, A₂ = 1, A₃ = 0

A₀ = 0, A₁ = 1, A₂ = 1, A₃ = 0

A₀ = 1, A₁ = 1, A₂ = 0, A₃ = 0

GATE ECE 2017 Set 2

MCQ (Single Correct Answer)

-0.3

Consider the circuit shown in the figure. GATE ECE 2017 Set 2 Digital Circuits - Combinational Circuits Question 37 English

The Boolean expression F implemented by the circuit is

$$\overline X \,\overline Y \,\overline Z + XY + \,\overline Y \,Z$$

$$\overline X \,Y\,\overline Z + XZ + \,\overline Y \,Z$$

$$\overline X \,Y\,\overline Z + XY + \,\overline Y \,Z$$

$$\overline X \,\overline Y \,\overline Z + XZ + \,\overline Y \,Z$$

GATE ECE 2016 Set 2

MCQ (Single Correct Answer)

-0.3

A 4:1 multiplexer is to be used for generating the output carry of a full adder. A and B are the bits to be added while 𝐶in is the input carry and 𝐶out is the output carry. A and B are to be used as the select bits with A being the more significant select bit. GATE ECE 2016 Set 2 Digital Circuits - Combinational Circuits Question 38 English

GATE ECE 2016 Set 2 Digital Circuits - Combinational Circuits Question 38 English

Which one of the following statements correctly describes the choice of signals to be connected to the inputs $${I_0}$$, $${I_1}$$, $${I_2 }$$ and $${I_3}$$ so that the output is C$$_{out}$$?

$${I_0} = 0,{I_0} = {C_{in}},\,{I_{2\,}} = {C_{in}}\,and\,{I_3} = I$$

$${I_0} = 1,\,{I_1}\, = {C_{in}},\,{I_{2\,}} = {C_{in}}\,and\,{I_3} = I$$

$${I_0} = {C_{in}},\,\,{I_{1\,}} = 0,\,{I_{2\,}} = 1and\,{I_3} = \,{C_{in}}$$

$${I_0} = 0,{I_1} = {C_{in}},\,{I_{2\,}} = \,2and\,{I_3} = {C_{in}}\,$$