The number of solutions of the pair of equations

$$2{\sin ^2}\theta - \cos 2\theta = 0$$

$$2{\cos ^2}\theta - 3\sin \theta = 0$$

in the interval $$[0,2\pi]$$ is

Let $$\theta \in\left(0, \frac{\pi}{4}\right)$$ and $$t_{1}=(\tan \theta)^{\tan \theta}, t_{2}=(\tan \theta)^{\cot \theta}, t_{3}=(\cot \theta)^{\tan \theta}$$ and $$t_{4}=(\cot \theta)^{\cot \theta}$$, then

If $0<\theta<2 \pi$, then the intervals of values of $\theta$ for which $2 \sin ^2 \theta-5 \sin \theta+2>0$, is