1
IIT-JEE 2006
MCQ (More than One Correct Answer)
+3
-1

A tangent drawn to the curve $y=f(x)$ at $\mathrm{P}(x, y)$ cuts the X -axis and Y -axis at A and B respectively such that $\mathrm{BP}: \mathrm{AP}=3: 1$, given that $f(1)=1$, then

A

equation of curve is $x \frac{d y}{d x}-3 y=0$

B

normal at $(1,1)$ is $x+3 y=4$

C

curve passes through $(2,1 / 8)$

D

equation of curve is $x \frac{d y}{d x}+3 y=0$

2
IIT-JEE 2006
MCQ (More than One Correct Answer)
+3
-1

$f(x)$ is cubic polynomial which has local maximum at $x=-1$. If $f(2)=18, f(1)=-1$ and $f(x)$ has local minima at $x=0$, then

A

the distance between $(-1,2)$ and $(a, f(A)$, where $x=a$ is the point of local minima is $2 \sqrt{5}$

B

$f(x)$ is increasing for $x \in[1,2 \sqrt{5}]$

C

$f(x)$ has local minima at $x=1$

D

the value of $f(0)=5$

3
IIT-JEE 2006
MCQ (More than One Correct Answer)
+3
-1

$$ \begin{aligned} & f(x)=\left\{\begin{array}{cc} e^x, & 0 \leq x \leq 1 \\ 2-e^{x-1}, & 1 < x \leq 2 \\ x-e, & 2 < x \leq 3 \end{array} \quad\right. \text { and } \\ & g(x)=\int_0^x f(t) d t, x \in[1,3] \text { then } g(x) \text { has } \end{aligned} $$

A

local maxima at $x=1+\ln 2$ and local $\operatorname{minima}$ at $x=e$

B

local maxima at $x=1$ and local minima at $x=2$

C

no local maxima

D

no local minima

4
IIT-JEE 1999
MCQ (More than One Correct Answer)
+3
-0.75
The function $$f\left( x \right) = \int\limits_{ - 1}^x {t\left( {{e^t} - 1} \right)\left( {t - 1} \right){{\left( {t - 2} \right)}^3}\,\,\,{{\left( {t - 3} \right)}^5}} $$ $$dt$$ has a local minimum at $$x=$$
A
$$0$$
B
$$1$$
C
$$2$$
D
$$3$$

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