JEE Advanced 2013 Paper 1 Offline | Application of Derivatives Question 26 | Mathematics

JEE Advanced 2013 Paper 1 Offline

MCQ (More than One Correct Answer)

-1

A rectangular sheet of fixed perimeter with sides having their lengths in the ratio $$8:15$$ is converted into an open rectangular box by folding after removing squares of equal area from all four corners. If the total area of removed squares is $$100$$, the resulting box has maximum volume. Then the lengths of the vsides of the rectangular sheet are

$$24$$

$$32$$

$$45$$

$$60$$

IIT-JEE 2012 Paper 2 Offline

MCQ (More than One Correct Answer)

-1

If $$f\left( x \right) = \int_0^x {{e^{{t^2}}}} \left( {t - 2} \right)\left( {t - 3} \right)dt$$ for all $$x \in \left( {0,\infty } \right),$$ then

$$f$$ has a local maximum at $$x=2$$

$$f$$ is decreasing on $$(2, 3)$$

there exists some $$c \in \left( {0,\infty } \right),$$ such that $$f'(c)=0$$

$$f$$ has a local minimum at $$x=3$$

IIT-JEE 2009 Paper 2 Offline

MCQ (More than One Correct Answer)

-2

For the function $$$f\left( x \right) = x\cos \,{1 \over x},x \ge 1,$$$

for at least one $$x$$ in the interval $$\left[ {1,\infty } \right)$$, $$f\left( {x + 2} \right) - f\left( x \right) < 2$$

$$\mathop {\lim }\limits_{x \to \infty } f'\left( x \right) = 1$$

for all $$x$$ in the interval $$\left[ {1,\infty } \right)f\left( {x + 2} \right) - f\left( x \right) > 2$$

$$f'(x)$$ is strictly decreasing in the interval $$\left[ {1,\infty } \right)$$

IIT-JEE 2006

MCQ (More than One Correct Answer)

-1

A tangent drawn to the curve $y=f(x)$ at $\mathrm{P}(x, y)$ cuts the X -axis and Y -axis at A and B respectively such that $\mathrm{BP}: \mathrm{AP}=3: 1$, given that $f(1)=1$, then

equation of curve is $x \frac{d y}{d x}-3 y=0$

normal at $(1,1)$ is $x+3 y=4$

curve passes through $(2,1 / 8)$

equation of curve is $x \frac{d y}{d x}+3 y=0$

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