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1

IIT-JEE 1986

Subjective
Lines 5x + 12y - 10 = 0 and 5x - 12y - 40 = 0 touch a circle $$C_1$$ of diameter 6. If the centre of $$C_1$$ lies in the first quadrant, find the equation of the circle $$C_2$$ which is concentric with $$C_1$$ and cuts intercepts of length 8 on these lines.

Answer

$${x^2}\, + \,{y^2} - \,10x\, - 4y + \,4 = 0\,$$
2

IIT-JEE 1984

Subjective
The abscissa of the two points A and B are the roots of the equation $${x^2}\, + \,2ax\, - {b^2} = 0$$ and their ordinates are the roots of the equation $${x^2}\, + \,2px\, - {q^2} = 0$$. Find the equation and the radius of the circle with AB as diameter.

Answer

$${x^2}\, + \,{y^2} + \,2ax\, + 2py\, - {b^2}\, - {q^2} = 0,\,\,\,\sqrt {{a^2}\, + \,{p^2} + {b^2}\, + \,{q^2}} $$
3

IIT-JEE 1983

Subjective
Through a fixed point (h, k) secants are drawn to the circle $$\,{x^2}\, + \,{y^2} = \,{r^2}$$. Show that the locus of the mid-points of the secants intercepted by the circle is $$\,{x^2}\, + \,{y^2} $$ = $$hx + ky$$.

Answer

solve it
4

IIT-JEE 1981

Subjective
Find the equations of the circle passing through (- 4, 3) and touching the lines x + y = 2 and x - y = 2.

Answer

$${x^2}\, + \,{y^2} + \,\,2\,\left( {10\,\, \pm \,\,\sqrt {54} } \right)\,x\, + \,\,55\,\, \pm \,\,\sqrt {54} = \,0$$

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