1
IIT-JEE 2012 Paper 2 Offline
MCQ (Single Correct Answer)
+4
-1
Four fair dice $${D_1,}$$ $${D_2,}$$ $${D_3}$$ and $${D_4}$$ ; each having six faces numbered $$1, 2, 3, 4, 5$$ and $$6$$ are rolled simultaneously. The probability that $${D_4}$$ shows a number appearing on one of $${D_1},$$ $${D_2}$$ and $${D_3}$$ is
A
$${{91} \over {216}}$$
B
$${{108} \over {216}}$$
C
$${{125} \over {216}}$$
D
$${{127} \over {216}}$$
2
IIT-JEE 2011 Paper 1 Offline
MCQ (Single Correct Answer)
+4
-1

Let $${U_1}$$ and $${U_2}$$ be two urns such that $${U_1}$$ contains $$3$$ white and $$2$$ red balls, and $${U_2}$$ contains only $$1$$ white ball. A fair coin is tossed. If head appears then $$1$$ ball is drawn at random from $${U_1}$$ and put into $${U_2}$$. However, if tail appears then $$2$$ balls are drawn at random from $${U_1}$$ and put into $${U_2}$$. Now $$1$$ ball is drawn at random from $${U_2}$$ being white is

The probability of the drawn ball from $${U_2}$$ being white is

A
$${{13} \over {30}}$$
B
$${{23} \over {30}}$$
C
$${{19} \over {30}}$$
D
$${{11} \over {30}}$$
3
IIT-JEE 2011 Paper 1 Offline
MCQ (Single Correct Answer)
+4
-1

Let $${U_1}$$ and $${U_2}$$ be two urns such that $${U_1}$$ contains $$3$$ white and $$2$$ red balls, and $${U_2}$$ contains only $$1$$ white ball. A fair coin is tossed. If head appears then $$1$$ ball is drawn at random from $${U_1}$$ and put into $${U_2}$$. However, if tail appears then $$2$$ balls are drawn at random from $${U_1}$$ and put into $${U_2}$$. Now $$1$$ ball is drawn at random from $${U_2}$$ being white is

Given that the drawn ball from $${U_2}$$ is white, the probability that head appeared on the coin is

A
$${{17} \over {23}}$$
B
$${{11} \over {23}}$$
C
$${{15} \over {23}}$$
D
$${{12} \over {23}}$$
4
IIT-JEE 2010 Paper 2 Offline
MCQ (Single Correct Answer)
+4
-1
A signal which can be green or red with probability $${4 \over 5}$$ and $${1 \over 5}$$ respectively, is received by station A and then transmitted to station $$B$$. The probability of each station receving the signal correctly is $${3 \over 4}$$. If the signal received at atation $$B$$ is green, then the probability that the original signal was green is
A
$${3 \over 5}$$
B
$${6 \over 7}$$
C
$${20 \over 23}$$
D
$${9 \over 20}$$
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