GATE ECE 2005 | Bipolar Junction Transistor Question 36 | Analog Circuits

GATE ECE 2005

MCQ (Single Correct Answer)

-0.6

The circuit using a BJT with β = 50 and V_BE = 0.7 V is shown in the figure. The base current I_B and collector voltage V_C are respectively GATE ECE 2005 Analog Circuits - Bipolar Junction Transistor Question 36 English

GATE ECE 2005 Analog Circuits - Bipolar Junction Transistor Question 36 English

43 μA and 11.4 Volts

40 μA and 16 Volts

45 μA and 11 Volts

50 μA and 10 Volts

GATE ECE 2004

MCQ (Single Correct Answer)

-0.6

A bipolar transistor is operating in the active region with a collector current of 1mA. Assuming that the 'β' of the transistor is 100 and the transconductance (g_m) and the input resistance ($${r_\pi }$$) of the transistor in the common emitter configuration, are

g_m = 25 mA/V and $${r_\pi }$$ = $$15.6\,\,k\Omega $$

g_m = 40 mA/V and $${r_\pi }$$ = $$4.0\,\,k\Omega $$

g_m = 25 mA/V and $${r_\pi }$$ = $$2.5\,\,k\Omega $$

g_m = 40 mA/V and $${r_\pi }$$ = $$2.5\,\,k\Omega $$

GATE ECE 2003

MCQ (Single Correct Answer)

-0.6

In the amplifier circuit shown in the figure, the values of R₁ and R₂ are such that the transistor is operating at V_CE = 3V and I_C = 1.5 mA when its $$\beta $$ is 150. For a transistor with $$\beta $$ of 200, the operating point (V_CE, I_C) is GATE ECE 2003 Analog Circuits - Bipolar Junction Transistor Question 40 English

GATE ECE 2003 Analog Circuits - Bipolar Junction Transistor Question 40 English

( 2 V , 2 mA)

( 3 V , 2 mA)

( 4 V , 2 mA)

( 2 V , 1 mA)

GATE ECE 2003

MCQ (Single Correct Answer)

-0.6

Three identical amplifiers with each one having a voltage gain of 50, input Resistance of 1 KΩ and output resistance of 250Ω, are cascaded. The open circuit voltage gain of the combined Amplifier is

49 dB

51 dB

98 dB

102 dB

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