1
GATE ECE 2005
+2
-0.6
For an npn transistor connected as shown in the figure, VBE = 0.7 volts. Given that reverse saturation current of the junction at room temperature $${300^0}$$ K is $${10^{ - 13}}\,{\rm A}$$, the emitter current is $$\left( {\eta \, = \,1} \right)$$
A
30 mA
B
39 mA
C
49 mA
D
20 mA
2
GATE ECE 2004
+2
-0.6
A bipolar transistor is operating in the active region with a collector current of 1mA. Assuming that the 'β' of the transistor is 100 and the transconductance (gm) and the input resistance ($${r_\pi }$$) of the transistor in the common emitter configuration, are
A
gm = 25 mA/V and $${r_\pi }$$ = $$15.6\,\,k\Omega$$
B
gm = 40 mA/V and $${r_\pi }$$ = $$4.0\,\,k\Omega$$
C
gm = 25 mA/V and $${r_\pi }$$ = $$2.5\,\,k\Omega$$
D
gm = 40 mA/V and $${r_\pi }$$ = $$2.5\,\,k\Omega$$
3
GATE ECE 2003
+2
-0.6
In the amplifier circuit shown in the figure, the values of R1 and R2 are such that the transistor is operating at VCE = 3V and IC = 1.5 mA when its $$\beta$$ is 150. For a transistor with $$\beta$$ of 200, the operating point (VCE, IC) is
A
( 2 V , 2 mA)
B
( 3 V , 2 mA)
C
( 4 V , 2 mA)
D
( 2 V , 1 mA)
4
GATE ECE 2003
+2
-0.6
Three identical amplifiers with each one having a voltage gain of 50, input Resistance of 1 KΩ and output resistance of 250Ω, are cascaded. The open circuit voltage gain of the combined Amplifier is
A
49 dB
B
51 dB
C
98 dB
D
102 dB
EXAM MAP
Medical
NEET