GATE ECE 2006 | Frequency Response Analysis Question 41 | Control Systems

GATE ECE 2006

MCQ (Single Correct Answer)

-0.6

Consider two transfer functions $${G_1}\left( s \right) = {1 \over {{s^2} + as + b}}$$ and $${G_2}\left( s \right) = {s \over {{s^2} + as + b}}.$$ The 3-dB bandwidths of their frequency responses are, respectively

$$\sqrt {{a^2} - 4b,} $$ $$\sqrt {{a^2} + 4b,} $$

$$\sqrt {{a^2} - 4b,} $$ $$\sqrt {{a^2} - 4b,} $$

$$\sqrt {{a^2} + 4b,} $$ $$\sqrt {{a^2} - 4b,} $$

$$\sqrt {{a^2} + 4b,} $$ $$\sqrt {{a^2} + 4b,} $$

GATE ECE 2005

MCQ (Single Correct Answer)

-0.6

The open loop transfer function of a unity feedback system is given by G(s)=$${{3{e^{ - 2s}}} \over {s\left( {s + 2} \right)}}.$$ The gain and phase crossover frequencies in rad/sec are, respectively

0.632 and 1.26

0.632 and 0.485

0.485 and 0.632

1.26 and 0.632

GATE ECE 2005

MCQ (Single Correct Answer)

-0.6

The polar diagram of a conditionally stable system for open loop gain K=1 is shown in figure. The open loop transfer function of the system is known to be stable. The closed loop system is stable for GATE ECE 2005 Control Systems - Frequency Response Analysis Question 37 English

GATE ECE 2005 Control Systems - Frequency Response Analysis Question 37 English

$$K < 5$$ and $${1 \over 2} < K < {1 \over 8}$$

$$K < {1 \over 8}and{1 \over 2} < K < 5$$

$$K < {1 \over 8}$$ and 5 < K

$$K > {1 \over 8}$$ and K < 5

GATE ECE 2005

MCQ (Single Correct Answer)

-0.6

The open loop transfer function of a unity feedback system is given by g(s)=$${{3{e^{ - 2s}}} \over {s\left( {s + 2} \right)}}.$$ Based on the above results, the gain and phase margins of the system will be

$$ - 7.09$$ dB and $${87.5^0}$$

$$ 7.09$$ dB and $${87.5^0}$$

$$ 7.09$$ dB and $${-87.5^0}$$

$$ - 7.09$$ dB and $${-87.5^0}$$

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