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1

IIT-JEE 2005 Screening

MCQ (Single Correct Answer)
The area bounded by the parabola $$y = {\left( {x + 1} \right)^2}$$ and
$$y = {\left( {x - 1} \right)^2}$$ and the line $$y=1/4$$ is
A
$$4$$ sq. units
B
$$1/6$$ sq. units
C
$$4/3$$ sq. units
D
$$1/3$$ sq. units
2

IIT-JEE 2005 Screening

MCQ (Single Correct Answer)
$$\int\limits_{ - 2}^0 {\left\{ {{x^3} + 3{x^2} + 3x + 3 + \left( {x + 1} \right)\cos \left( {x + 1} \right)} \right\}\,\,dx} $$ is equal to
A
$$-4$$
B
$$0$$
C
$$4$$
D
$$6$$
3

IIT-JEE 2004 Screening

MCQ (Single Correct Answer)
If $$f(x)$$ is differentiable and $$\int\limits_0^{{t^2}} {xf\left( x \right)dx = {2 \over 5}{t^5},} $$ then $$f\left( {{4 \over {25}}} \right)$$ equals
A
$$2/5$$
B
$$-5/2$$
C
$$1$$
D
$$5/2$$
4

IIT-JEE 2004 Screening

MCQ (Single Correct Answer)
The area enclosed between the curves $$y = a{x^2}$$ and
$$x = a{y^2}\left( {a > 0} \right)$$ is $$1$$ sq. unit, then the value of $$a$$ is
A
$$1/\sqrt 3 $$
B
$$1/2$$
C
$$1$$
D
$$1/3$$

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