IIT-JEE 1982 | Application of Integration Question 54 | Mathematics

IIT-JEE 1982

MCQ (Single Correct Answer)

-0.5

The area bounded by the curves $$y=f(x)$$, the $$x$$-axis and the ordinates $$x=1$$ and $$x=b$$ is $$(b-1)$$ sin $$(3b+4)$$. Then $$f(x)$$ is

$$\left( {x - 1} \right)\cos \left( {3x + 4} \right)$$

$$\sin \left( {3x + 4} \right)$$

$$\sin \left( {3x + 4} \right) + 3\left( {x - 1} \right)\cos \left( {3x + 4} \right)$$

none of these

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