1
GATE ECE 1995
MCQ (Single Correct Answer)
+1
-0.3
The minimum number of NAND gates required to implement the Boolean function $$A + A\overline B $$ $$ + A\overline B C$$ is equal to
A
Zero
B
1
C
4
D
7
2
GATE ECE 1994
Fill in the Blanks
+1
-0
A ring oscillator consisting of 5 inverters is running at a frequency of 1.0 MH$$_z$$. The progagation delay per gate is ______
3
GATE ECE 1993
MCQ (Single Correct Answer)
+1
-0.3
For the logic circuit shown in Figure, the output is equal to GATE ECE 1993 Digital Circuits - Logic Gates Question 34 English
A
$$\overline A \,.\overline B .\overline C $$
B
$$\overline A \, + \overline B + \overline C $$
C
$$\overline {AB} + \overline {BC} + \overline A + \overline C $$
D
$$\overline {AB} + \overline {BC} $$
4
GATE ECE 1993
MCQ (More than One Correct Answer)
+1
-0.3
Boolean expression for the output of XNOR (equivalence) logic gate with inputs A and B is
A
$$A\overline B + \overline A B$$
B
$$\overline A \,\overline B + AB$$
C
$$(\overline A + B)(A + \overline B )$$
D
$$(\overline A \, + \overline B )(A + B)$$
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