1
GATE ECE 2008
+2
-0.6
In the following circuit, the comparator output is logic “I” if V1 > V2 and is logic “0” otherwise. The D/A conversion is done as per the relation $${V_{DAC}} = \sum\limits_{n = 0}^3 {{2^{n - 1}}{b_n}\,\,} Volts,$$$where b3(MSB), b2, b1 and b0 (LSB) are the counter outputs. The counter starts from the clear state. The magnitude of the error between VDAC and Vin at steady state in volts is A 0.2 B 0.3 C 0.5 D 1 2 GATE ECE 2008 MCQ (Single Correct Answer) +2 -0.6 In the following circuit, the comparator output is logic “I” if V1 > V2 and is logic “0” otherwise. The D/A conversion is done as per the relation $${V_{DAC}} = \sum\limits_{n = 0}^3 {{2^{n - 1}}{b_n}\,\,} Volts,$$$ where b3(MSB), b2, b1 and b0 (LSB) are the counter outputs.

The counter starts from the clear state.

The stable reading of the LED display is

A
06
B
07
C
12
D
13
3
GATE ECE 2007
+2
-0.6
In the digital-to-Analog converter circuit shown in the figure below,
$${V_{R\,}}\, = \,10V$$ and $$R\, = \,10k\Omega$$

The current i is

A
$$31.25\,\mu {\rm A}$$
B
$$62.5\,\mu {\rm A}$$
C
$$125\,\mu {\rm A}$$
D
$$250\,\mu {\rm A}$$
4
GATE ECE 2007
+2
-0.6
In the digital-to-Analog converter circuit shown in the figure below,
$${V_{R\,}}\, = \,10V$$ and $$R\, = \,10k\Omega$$

The voltage V0 is

A
-0.781V
B
-1.562V
C
-3.125V
D
-6.250V
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