1
JEE Advanced 2024 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

List-I contains various reaction sequences and List-II contains different phenolic compounds. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.

List-I List-II
JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 1 English 1 JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 1 English 2
JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 1 English 3 JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 1 English 4
JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 1 English 5 JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 1 English 6
JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 1 English 7 JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 1 English 8
JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 1 English 9
A
P-2, Q-3, R-4, S-5
B
P-2, Q-3, R-5, S-1
C
P-3, Q-5, R-4, S-1
D
P-3, Q-2, R-5, S-4
2
JEE Advanced 2024 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

Let $f(x)$ be a continuously differentiable function on the interval $(0, \infty)$ such that $f(1)=2$ and

$$ \lim\limits_{t \rightarrow x} \frac{t^{10} f(x)-x^{10} f(t)}{t^9-x^9}=1 $$

for each $x>0$. Then, for all $x>0, f(x)$ is equal to :

A
$\frac{31}{11 x}-\frac{9}{11} x^{10}$
B
$\frac{9}{11 x}+\frac{13}{11} x^{10}$
C
$\frac{-9}{11 x}+\frac{31}{11} x^{10}$
D
$\frac{13}{11 x}+\frac{9}{11} x^{10}$
3
JEE Advanced 2024 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

A student appears for a quiz consisting of only true-false type questions and answers all the questions. The student knows the answers of some questions and guesses the answers for the remaining questions. Whenever the student knows the answer of a question, he gives the correct answer. Assume that the probability of the student giving the correct answer for a question, given that he has guessed it, is $\frac{1}{2}$. Also assume that the probability of the answer for a question being guessed, given that the student's answer is correct, is $\frac{1}{6}$. Then the probability that the student knows the answer of a randomly chosen question is :

A
$\frac{1}{12}$
B
$\frac{1}{7}$
C
$\frac{5}{7}$
D
$\frac{5}{12}$
4
JEE Advanced 2024 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

Let $\frac{\pi}{2} < x < \pi$ be such that $\cot x=\frac{-5}{\sqrt{11}}$. Then

$$ \left(\sin \frac{11 x}{2}\right)(\sin 6 x-\cos 6 x)+\left(\cos \frac{11 x}{2}\right)(\sin 6 x+\cos 6 x) $$

is equal to :

A
$\frac{\sqrt{11}-1}{2 \sqrt{3}}$
B
$\frac{\sqrt{11}+1}{2 \sqrt{3}}$
C
$\frac{\sqrt{11}+1}{3 \sqrt{2}}$
D
$\frac{\sqrt{11}-1}{3 \sqrt{2}}$
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