In a conductometric titration, small volume of titrant of higher concentration is added stepwise to a larger volume of titrate of much lower concentration, and the conductance is measured after each addition.
The limiting ionic conductivity $\left(\Lambda_0\right)$ values (in $\mathrm{mS} \mathrm{m}{ }^2 \mathrm{~mol}^{-1}$ ) for different ions in aqueous solutions are given below:
$$ \begin{array}{|c|c|c|c|c|c|c|c|c|c|} \hline \text { Ions } & \mathrm{Ag}^{+} & \mathrm{K}^{+} & \mathrm{Na}^{+} & \mathrm{H}^{+} & \mathrm{NO}_3^{-} & \mathrm{Cl}^{-} & \mathrm{SO}_4^{2-} & \mathrm{OH}^{-} & \mathrm{CH}_3 \mathrm{COO}^{-} \\ \hline \Lambda_0 & 6.2 & 7.4 & 5.0 & 35.0 & 7.2 & 7.6 & 16.0 & 19.9 & 4.1 \\ \hline \end{array} $$
For different combinations of titrates and titrants given in List-I, the graphs of 'conductance' versus 'volume of titrant' are given in List-II.
Match each entry in List-I with the appropriate entry in List-II and choose the correct option.
LIST-I | LIST-II |
---|---|
(P) Titrate: KCl Titrant: AgNO$_3$ |
|
(Q) Titrate: AgNO$_3$ Titrant: KCl |
|
(R) Titrate: NaOH Titrant: HCl |
|
(S) Titrate: NaOH Titrant: CH$_3$COOH |
|
Based on VSEPR model, match the xenon compounds given in List-I with the corresponding geometries and the number of lone pairs on xenon given in List-II and choose the correct option.
List-I | List-II |
---|---|
(P) XeF$_2$ | (1) Trigonal bipyramidal and two lone pair of electrons |
(Q) XeF$_4$ | (2) Tetrahedral and one lone pair of electrons |
(R) XeO$_3$ | (3) Octahedral and two lone pair of electrons |
(S) XeO$_3$F$_2$ | (4) Trigonal bipyramidal and no lone pair of electrons |
(5) Trigonal bipyramidal and three lone pair of electrons |
List-I contains various reaction sequences and List-II contains the possible products. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.
List-I | List-II |
---|---|
List-I contains various reaction sequences and List-II contains different phenolic compounds. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.
List-I | List-II |
---|---|