1
JEE Advanced 2024 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language
Aspartame, an artificial sweetener, is a dipeptide aspartyl phenylalanine methyl ester. The structure of aspartame is

JEE Advanced 2024 Paper 1 Online Chemistry - Chemistry in Everyday Life Question 1 English
A
JEE Advanced 2024 Paper 1 Online Chemistry - Chemistry in Everyday Life Question 1 English Option 1
B
JEE Advanced 2024 Paper 1 Online Chemistry - Chemistry in Everyday Life Question 1 English Option 2
C
JEE Advanced 2024 Paper 1 Online Chemistry - Chemistry in Everyday Life Question 1 English Option 3
D
JEE Advanced 2024 Paper 1 Online Chemistry - Chemistry in Everyday Life Question 1 English Option 4
2
JEE Advanced 2024 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

Among the following options, select the option in which each complex in Set-I shows geometrical isomerism and the two complexes in Set-II are ionization isomers of each other.

$$ \text { [en }=\mathrm{H}_2 \mathrm{NCH}_2 \mathrm{CH}_2 \mathrm{NH}_2 \text { ] } $$

A

Set-I: $\left[\mathrm{Ni}(\mathrm{CO})_4\right]$ and $\left[\mathrm{PdCl}_2\left(\mathrm{PPh}_3\right)_2\right]$

Set-II: $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{SO}_4$ and $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{SO}_4\right)\right] \mathrm{Cl}$

B

Set-I: $\left[\mathrm{Co}(\mathrm{en})\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}_2\right]$ and $\left[\mathrm{PdCl}_2\left(\mathrm{PPh}_3\right)_2\right]$

Set-II: $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]\left[\mathrm{Cr}(\mathrm{CN})_6\right]$ and $\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]\left[\mathrm{Co}(\mathrm{CN})_6\right]$

C

Set-I: $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3\left(\mathrm{NO}_2\right)_3\right]$ and $\left[\mathrm{Co}(\mathrm{en})_2 \mathrm{Cl}_2\right]$

Set-II: $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{SO}_4$ and $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{SO}_4\right)\right] \mathrm{Cl}$

D

Set-I: $\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2$ and $\left[\mathrm{Co}(\mathrm{en})\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}_2\right]$

Set-II: $\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3$ and $\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2 \cdot \mathrm{H}_2 \mathrm{O}$

3
JEE Advanced 2024 Paper 1 Online
MCQ (More than One Correct Answer)
+4
-2
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Among the following, the correct statement(s) for electrons in an atom is(are)

A
Uncertainty principle rules out the existence of definite paths for electrons.
B
The energy of an electron in $2 s$ orbital of an atom is lower than the energy of an electron that is infinitely far away from the nucleus.
C
According to Bohr's model, the most negative energy value for an electron is given by $\mathrm{n}=1$, which corresponds to the most stable orbit.
D
According to Bohr's model, the magnitude of velocity of electrons increases with increase in values of $n$.
4
JEE Advanced 2024 Paper 1 Online
MCQ (More than One Correct Answer)
+4
-2
Change Language

Reaction of iso-propylbenzene with $\mathrm{O}_2$ followed by the treatment with $\mathrm{H}_3 \mathrm{O}^{+}$forms phenol and a by-product $\mathbf{P}$. Reaction of $\mathbf{P}$ with 3 equivalents of $\mathrm{Cl}_2$ gives compound $\mathbf{Q}$. Treatment of $\mathbf{Q}$ with $\mathrm{Ca}(\mathrm{OH})_2$ produces compound $\mathbf{R}$ and calcium salt $\mathbf{S}$.

The correct statement(s) regarding $\mathbf{P}, \mathbf{Q}, \mathbf{R}$ and $\mathbf{S}$ is(are)

A
Reaction of $\mathbf{P}$ with $\mathbf{R}$ in the presence of $\mathrm{KOH}$ followed by acidification gives JEE Advanced 2024 Paper 1 Online Chemistry - Alcohols, Phenols and Ethers Question 1 English Option 1
B
Reaction of $\mathbf{R}$ with $\mathrm{O}_2$ in the presence of light gives phosgene gas
C
$\mathbf{Q}$ reacts with aqueous $\mathrm{NaOH}$ to produce $\mathrm{Cl}_3 \mathrm{CCH}_2 \mathrm{OH}$ and $\mathrm{Cl}_3 \mathrm{CCOONa}$
D
$\mathbf{S}$ on heating gives $\mathbf{P}$
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