1
JEE Advanced 2024 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

Based on VSEPR model, match the xenon compounds given in List-I with the corresponding geometries and the number of lone pairs on xenon given in List-II and choose the correct option.

List-I List-II
(P) XeF$_2$ (1) Trigonal bipyramidal and two lone pair of electrons
(Q) XeF$_4$ (2) Tetrahedral and one lone pair of electrons
(R) XeO$_3$ (3) Octahedral and two lone pair of electrons
(S) XeO$_3$F$_2$ (4) Trigonal bipyramidal and no lone pair of electrons
(5) Trigonal bipyramidal and three lone pair of electrons
A
P-5, Q-2, R-3, S-1
B
P-5, Q-3, R-2, S-4
C
P-4, Q-3, R-2, S-1
D
P-4, Q-2, R-5, S-3
2
JEE Advanced 2024 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

List-I contains various reaction sequences and List-II contains the possible products. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.

List-I List-II
JEE Advanced 2024 Paper 1 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 4 English 1 JEE Advanced 2024 Paper 1 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 4 English 2
JEE Advanced 2024 Paper 1 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 4 English 3 JEE Advanced 2024 Paper 1 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 4 English 4
JEE Advanced 2024 Paper 1 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 4 English 5 JEE Advanced 2024 Paper 1 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 4 English 6
JEE Advanced 2024 Paper 1 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 4 English 7 JEE Advanced 2024 Paper 1 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 4 English 8
JEE Advanced 2024 Paper 1 Online Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 4 English 9
A
P-3, Q-5, R-4, S-1
B
P-3, Q-2, R-4, S-1
C
P-3, Q-5, R-1, S-4
D
P-5, Q-2, R-4, S-1
3
JEE Advanced 2024 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

List-I contains various reaction sequences and List-II contains different phenolic compounds. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.

List-I List-II
JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 3 English 1 JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 3 English 2
JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 3 English 3 JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 3 English 4
JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 3 English 5 JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 3 English 6
JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 3 English 7 JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 3 English 8
JEE Advanced 2024 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 3 English 9
A
P-2, Q-3, R-4, S-5
B
P-2, Q-3, R-5, S-1
C
P-3, Q-5, R-4, S-1
D
P-3, Q-2, R-5, S-4
4
JEE Advanced 2024 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

Let $f(x)$ be a continuously differentiable function on the interval $(0, \infty)$ such that $f(1)=2$ and

$$ \lim\limits_{t \rightarrow x} \frac{t^{10} f(x)-x^{10} f(t)}{t^9-x^9}=1 $$

for each $x>0$. Then, for all $x>0, f(x)$ is equal to :

A
$\frac{31}{11 x}-\frac{9}{11} x^{10}$
B
$\frac{9}{11 x}+\frac{13}{11} x^{10}$
C
$\frac{-9}{11 x}+\frac{31}{11} x^{10}$
D
$\frac{13}{11 x}+\frac{9}{11} x^{10}$
JEE Advanced Papers
EXAM MAP
Medical
NEETAIIMS
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
Defence
NDA
Staff Selection Commission
SSC CGL Tier I
CBSE
Class 12