1
JEE Advanced 2024 Paper 1 Online
Numerical
+4
-0
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Among $\mathrm{V}(\mathrm{CO})_6, \mathrm{Cr}(\mathrm{CO})_5, \mathrm{Cu}(\mathrm{CO})_3, \mathrm{Mn}(\mathrm{CO})_5, \mathrm{Fe}(\mathrm{CO})_5,\left[\mathrm{Co}(\mathrm{CO})_3\right]^{3-},\left[\mathrm{Cr}(\mathrm{CO})_4\right]^{4-}$, and $\operatorname{Ir}(\mathrm{CO})_3$, the total number of species isoelectronic with $\mathrm{Ni}(\mathrm{CO})_4$ is _________.

[Given, atomic number: $\mathrm{V}=23, \mathrm{Cr}=24, \mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Co}=27, \mathrm{Ni}=28, \mathrm{Cu}=29, \mathrm{Ir}=77$ ]

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2
JEE Advanced 2024 Paper 1 Online
Numerical
+4
-0
Change Language

In the following reaction sequence, the major product $\mathbf{P}$ is formed.

JEE Advanced 2024 Paper 1 Online Chemistry - Hydrocarbons Question 1 English

Glycerol reacts completely with excess $\mathbf{P}$ in the presence of an acid catalyst to form $\mathbf{Q}$. Reaction of $\mathbf{Q}$ with excess $\mathrm{NaOH}$ followed by the treatment with $\mathrm{CaCl}_2$ yields Ca-soap $\mathbf{R}$, quantitatively. Starting with one mole of $\mathbf{Q}$, the amount of $\mathbf{R}$ produced in gram is __________.

[Given, atomic weight: $\mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{O}=16, \mathrm{Na}=23, \mathrm{Cl}=35, \mathrm{Ca}=40$ ]

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3
JEE Advanced 2024 Paper 1 Online
Numerical
+4
-0
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Among the following complexes, the total number of diamagnetic species is ___________.

$\left[\mathrm{Mn}\left(\mathrm{NH}_3\right)_6\right]^{3+},\left[\mathrm{MnCl}_6\right]^{3-},\left[\mathrm{FeF}_6\right]^{3-},\left[\mathrm{CoF}_6\right]^{3-},\left[\mathrm{Fe}\left(\mathrm{NH}_3\right)_6\right]^{3+}$, and $\left[\mathrm{Co}(\mathrm{en})_3\right]^{3+}$

[Given, atomic number: $\mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Co}=27$;

$$ \text { en } \left.=\mathrm{H}_2 \mathrm{NCH}_2 \mathrm{CH}_2 \mathrm{NH}_2\right] $$

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4
JEE Advanced 2024 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
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In a conductometric titration, small volume of titrant of higher concentration is added stepwise to a larger volume of titrate of much lower concentration, and the conductance is measured after each addition.

The limiting ionic conductivity $\left(\Lambda_0\right)$ values (in $\mathrm{mS} \mathrm{m}{ }^2 \mathrm{~mol}^{-1}$ ) for different ions in aqueous solutions are given below:

$$ \begin{array}{|c|c|c|c|c|c|c|c|c|c|} \hline \text { Ions } & \mathrm{Ag}^{+} & \mathrm{K}^{+} & \mathrm{Na}^{+} & \mathrm{H}^{+} & \mathrm{NO}_3^{-} & \mathrm{Cl}^{-} & \mathrm{SO}_4^{2-} & \mathrm{OH}^{-} & \mathrm{CH}_3 \mathrm{COO}^{-} \\ \hline \Lambda_0 & 6.2 & 7.4 & 5.0 & 35.0 & 7.2 & 7.6 & 16.0 & 19.9 & 4.1 \\ \hline \end{array} $$

For different combinations of titrates and titrants given in List-I, the graphs of 'conductance' versus 'volume of titrant' are given in List-II.

Match each entry in List-I with the appropriate entry in List-II and choose the correct option.

LIST-I LIST-II
(P) Titrate: KCl
Titrant: AgNO$_3$
JEE Advanced 2024 Paper 1 Online Chemistry - Electrochemistry Question 1 English 1
(Q) Titrate: AgNO$_3$
Titrant: KCl
JEE Advanced 2024 Paper 1 Online Chemistry - Electrochemistry Question 1 English 2
(R) Titrate: NaOH
Titrant: HCl
JEE Advanced 2024 Paper 1 Online Chemistry - Electrochemistry Question 1 English 3
(S) Titrate: NaOH
Titrant: CH$_3$COOH
JEE Advanced 2024 Paper 1 Online Chemistry - Electrochemistry Question 1 English 4
JEE Advanced 2024 Paper 1 Online Chemistry - Electrochemistry Question 1 English 5
A
P-4, Q-3, R-2, S-5
B
P-2, Q-4, R-3, S-1
C
P-3, Q-4, R-2, S-5
D
P-4, Q-3, R-2, S-1
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