The sum of the number of lone pairs of electrons on each central atom in the following species is

$${[TeB{r_6}]^{2 - }},{\left[ {Br{F_2}} \right]^ + },SNF_3,$$ and $${\left[ {Xe{F_3}} \right]^ - }$$

(Atomic numbers: $$N = 7,F = 9,$$ $$S = 16,Br = 35,$$ $$Te = 52,Xe = 54$$)

Among $${H_2},H{e_2}^ + ,L{i_2},$$ $$B{e_2},{B_2},{C_2},{N_2},O_2^ - $$ and $${F_2},$$ the number of diamagnetic species is

(Atomic numbers : $$H = 1,He = 2,$$ $$Li = 3,Be = 4,$$ $$B = 5,C = 6,$$ $$N = 7,$$ $$O = 8,F = 9$$)

Columns 1, 2 and 3 contain starting materials, reaction conditions, and type of reactions, respectively.

	Column 1		Column 2		Column 3
(I)	Toluene	(i)	NaOH/Br2	(P)	Condensation
(II)	Acetophenone	(ii)	Br2/hv	(Q)	Carboxylation
(III)	Benzaldehyde	(iii)	(CH3CO)2O/ CH3COOK	(R)	Substitution
(IV)	Phenol	(iv)	NaOH/CO2	(S)	Haloform

For the synthesis of benzoic acid, the only CORRECT combination is

The IUPAC name(s) of the following compound is (are)