1
JEE Advanced 2017 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
Change Language
A block of mass $$M$$ has a circular cut with a frictionless surface as shown. The block resets on the horizontal frictionless surface of a fixed table. Initially the right edge of the block is at $$x=0,$$ in a co-ordinate system fixed to the table. A point mass $$m$$ is released from rest at the topmost point of the path as shown and it slides down.

When the mass loses contact with the block, its position is $$x$$ and the velocity is $$v.$$ At that instant, which of the following options is/are correct?

JEE Advanced 2017 Paper 1 Offline Physics - Rotational Motion Question 44 English
A
The position of the point mass $$m$$ is :

$$x = - \sqrt 2 {{mR} \over {M + m}}$$
B
The velocity of the point mass $$m$$ is :

$$v = \sqrt {{{2gR} \over {1 + {m \over M}}}} $$
C
The $$x$$ component of displacement of the center

of mass of the block $$M$$ is: $$ - {{mR} \over {M + m}}$$
D
The velocity of the block $$M$$ is:

$$V = - {m \over M}\sqrt {2gR} $$
2
JEE Advanced 2017 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-2
Change Language
A human body has a surface area of approximately $$1\,m{}^2.$$ The normal body temperature is $$10$$ $$K$$ above the surrounding room temperature $${T_0}.$$ Take the room temperature to be $${T_0} = 300K.$$ For $${T_0} = 300\,K,$$ the value of $$\sigma T_0^4 = 460\,W{m^{ - 2}}$$ (where $$\sigma $$ is the Stefan-Boltzmann constant).

Which of the following options is / are correct?
A
The amount of energy radiated by the body in $$1$$ second is close to $$60$$ joules
B
If the surrounding temperature reduces by a small amount $$\Delta {T_0} < < {T_0},$$ then to maintain the same body temperature the same (living) human being needs to radiate $$\Delta W = 4\sigma T_0^3\Delta {T_0}$$ more energy per unit time
C
Reducing the exposed surface area of the body (e.g. by curling up) allows human to maintain the same body temperature while reducing the energy lost by radiation
D
If the body temperature rises significantly then the peak in the spectrum of electromagnetic radiation emitted by the body would shift to longer wavelengths
3
JEE Advanced 2017 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
Change Language
A circular insulated copper wire loop is twisted to form two loops of area $$A$$ and $$2A$$ as shown in the figure. At the point of crossing the wires remain electrically insulated from each other. The entire loop lies in the plane (of the paper). A uniform magnetic field $$\overrightarrow B $$ points into the plane of the paper. At $$t=0,$$ the loop starts rotating about the common diameter as axis with a constant angular velocity $$\omega $$ in the magnetic field.

Which of the following options is/are correct?

JEE Advanced 2017 Paper 1 Offline Physics - Electromagnetic Induction Question 15 English
A
The emf induced in the loop is proportional to the sum of the areas of the two loops
B
The amplitude of the maximum net emf induced due to both the loops is equal to the amplitude if maximum emf induced in the smaller loop alone
C
The net emf induced due to both the loops is proportional to $$\cos \,\omega t$$
D
The rate of change of the flux is maximum when the plane of the loops is perpendicular to plane of the paper
4
JEE Advanced 2017 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
Change Language
For an isosceles prism of angle $$A$$ and refractive index $$\mu $$, it is found that the angle of minimum deviation $${\delta _m} = A.$$

Which of the following options is/are correct?
A
For the angle of incidence $${i_1} = A,$$ the ray inside the prism is parallel to the base of the prism
B
For this prism, the refractive index $$\mu $$ and the angle of prism $$A$$ are related as

$$A = {1 \over 2}{\cos ^{ - 1}}\left( {{\mu \over 2}} \right)$$
C
At minimum deviation, the incident angle $${i_1}$$ and the refracting angle $${r_1}$$ at the first refracting surface are related by $${r_1} = \left( {{i_1}/2} \right)$$
D
For this prism, the emergent ray at the second surface will be tangential to the surface when the angle of incidence at the first surface is

$${i_1} = {\sin ^{ - 1}}\left[ {\sin A\sqrt {4{{\cos }^2}{A \over 2} - 1} - \cos A} \right]$$
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