JEE Advanced 2017 Paper 1 Offline | JEE Advanced Year Wise Previous Years Questions

JEE Advanced 2017 Paper 1 Offline

MCQ (More than One Correct Answer)

-2

A human body has a surface area of approximately $$1\,m{}^2.$$ The normal body temperature is $$10$$ $$K$$ above the surrounding room temperature $${T_0}.$$ Take the room temperature to be $${T_0} = 300K.$$ For $${T_0} = 300\,K,$$ the value of $$\sigma T_0^4 = 460\,W{m^{ - 2}}$$ (where $$\sigma $$ is the Stefan-Boltzmann constant).

Which of the following options is / are correct?

The amount of energy radiated by the body in $$1$$ second is close to $$60$$ joules

If the surrounding temperature reduces by a small amount $$\Delta {T_0} < < {T_0},$$ then to maintain the same body temperature the same (living) human being needs to radiate $$\Delta W = 4\sigma T_0^3\Delta {T_0}$$ more energy per unit time

Reducing the exposed surface area of the body (e.g. by curling up) allows human to maintain the same body temperature while reducing the energy lost by radiation

If the body temperature rises significantly then the peak in the spectrum of electromagnetic radiation emitted by the body would shift to longer wavelengths

JEE Advanced 2017 Paper 1 Offline

MCQ (More than One Correct Answer)

-1

A circular insulated copper wire loop is twisted to form two loops of area $$A$$ and $$2A$$ as shown in the figure. At the point of crossing the wires remain electrically insulated from each other. The entire loop lies in the plane (of the paper). A uniform magnetic field $$\overrightarrow B $$ points into the plane of the paper. At $$t=0,$$ the loop starts rotating about the common diameter as axis with a constant angular velocity $$\omega $$ in the magnetic field.

Which of the following options is/are correct?

JEE Advanced 2017 Paper 1 Offline Physics - Electromagnetic Induction Question 16 English

JEE Advanced 2017 Paper 1 Offline Physics - Electromagnetic Induction Question 16 English

The emf induced in the loop is proportional to the sum of the areas of the two loops

The amplitude of the maximum net emf induced due to both the loops is equal to the amplitude if maximum emf induced in the smaller loop alone

The net emf induced due to both the loops is proportional to $$\cos \,\omega t$$

The rate of change of the flux is maximum when the plane of the loops is perpendicular to plane of the paper

JEE Advanced 2017 Paper 1 Offline

MCQ (More than One Correct Answer)

-1

For an isosceles prism of angle $$A$$ and refractive index $$\mu $$, it is found that the angle of minimum deviation $${\delta _m} = A.$$

Which of the following options is/are correct?

For the angle of incidence $${i_1} = A,$$ the ray inside the prism is parallel to the base of the prism

For this prism, the refractive index $$\mu $$ and the angle of prism $$A$$ are related as

$$A = {1 \over 2}{\cos ^{ - 1}}\left( {{\mu \over 2}} \right)$$

At minimum deviation, the incident angle $${i_1}$$ and the refracting angle $${r_1}$$ at the first refracting surface are related by $${r_1} = \left( {{i_1}/2} \right)$$

For this prism, the emergent ray at the second surface will be tangential to the surface when the angle of incidence at the first surface is

$${i_1} = {\sin ^{ - 1}}\left[ {\sin A\sqrt {4{{\cos }^2}{A \over 2} - 1} - \cos A} \right]$$

JEE Advanced 2017 Paper 1 Offline

MCQ (More than One Correct Answer)

-1

In the circuit shown, $$L = 1\,\mu H,C = 1\,\mu F\,$$ and $$R = 1\,k\Omega .$$ They are connected in series with an a.c. source $$V = {V_0}\sin \omega t$$ as shown.

Which of the following options is/are correct?

JEE Advanced 2017 Paper 1 Offline Physics - Alternating Current Question 13 English