1
MHT CET 2026 19th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The value of $\lim\limits_{x \to 0}\left(\dfrac{8}{x^8}\right)\left[1 - \cos\dfrac{x^2}{2} - \cos\dfrac{x^2}{4} + \cos\dfrac{x^2}{2}\cdot\cos\dfrac{x^2}{4}\right]$ is equal to ...
A
$\dfrac{1}{8}$
B
$\dfrac{1}{32}$
C
$\dfrac{1}{16}$
D
$0$
2
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $\lim\limits_{x \to k} \dfrac{x^3 - k^3}{x^2 - k^2} = \lim\limits_{x \to 0} \dfrac{1 - \cos(2x)}{x \sin x}$, then the value of $k$ is $\ldots$
A
$\dfrac{4}{3}$
B
$\dfrac{3}{4}$
C
$\dfrac{8}{3}$
D
$\dfrac{3}{8}$
3
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $f(x) = \dfrac{3^x + 3^{-x} - 2}{\tan x \cdot \log(1+x)}$ for $x \neq 0$, is continuous at $x = 0$, then the value of $f(0)$ is equal to $\ldots$
A
$2\log 3$
B
$(\log 3)^2$
C
$\dfrac{1}{2}\log 3$
D
$\log \dfrac{1}{3}$
4
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $\lim\limits_{x \to \infty}\left[\dfrac{x^2+x+1}{x+1} - ax - b\right] = 3$, then $a - b = $...
A
$2$
B
$3$
C
$-2$
D
$4$

MHT CET Subjects

Browse all chapters by subject