Probability · Mathematics · MHT CET

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MCQ (Single Correct Answer)

1

If a discrete random variable X is defined as follows

$\mathrm{P}[\mathrm{X}=x]=\left\{\begin{array}{cl}\frac{\mathrm{k}(x+1)}{5^x}, & \text { if } x=0,1,2 \ldots \ldots . \\ 0, & \text { otherwise }\end{array}\right.$

then $\mathrm{k}=$

MHT CET 2024 16th May Evening Shift
2

Numbers are selected at random, one at a time from two digit numbers $10,11,12 \ldots ., 99$ with replacement. An event $E$ occurs if and only if the product of the two digits of a selected number is 18 . If four numbers are selected, then probability that the event E occurs at least 3 times is

MHT CET 2024 16th May Evening Shift
3

Two friends A and B apply for a job in the same company. The probabilities of A getting selected is $\frac{2}{5}$ and that of B is $\frac{4}{7}$. Then the probability, that one of them is selected, is

MHT CET 2024 16th May Evening Shift
4

If a random variable X has the following probability distribution values

$\mathrm{X}$ 0 1 2 3 4 5 6 7
$\mathrm{P(X):}$ 0 $\mathrm{k}$ $\mathrm{2k}$ $\mathrm{2k}$ $\mathrm{3k}$ $\mathrm{k^2}$ $\mathrm{2k^2}$ $\mathrm{7k^2+k}$

Then $P(X \geq 6)$ has the value

MHT CET 2024 16th May Morning Shift
5

A random variable X takes the values $0,1,2,3$ and its mean is 1.3 . If $\mathrm{P}(\mathrm{X}=3)=2 \mathrm{P}(\mathrm{X}=1)$ and $P(X=2)=0.3$, then $P(X=0)$ is

MHT CET 2024 16th May Morning Shift
6

Three persons $\mathrm{P}, \mathrm{Q}$ and R independently try to hit a target. If the probabilities of their hitting the target are $\frac{3}{4}, \frac{1}{2}$ and $\frac{5}{8}$ respectively, then the probability that the target is hit by P or Q but not by $R$, is

MHT CET 2024 16th May Morning Shift
7

A box contains 15 green and 10 yellow balls. If 10 balls are randomly drawn, one by one, with replacement, then the variance of the number of green balls drawn is

MHT CET 2024 16th May Morning Shift
8
 

Suppose three coins are tossed simultaneously. If $X$ denotes the number of heads, then probability distribution of x is

MHT CET 2024 15th May Evening Shift
9

Four fair dice are thrown independently 27 times. Then the expected number of times, at least two dice show up a three or a five is

MHT CET 2024 15th May Evening Shift
10

If two fair dice are rolled, then the probability that the sum of the numbers on the upper faces is at least 9, is

MHT CET 2024 15th May Evening Shift
11

For the probability distribution

$x :$ 0 1 2 3 4 5
$p(x):$ $\mathrm{k}$ 0.3 0.15 0.15 0.1 2$\mathrm{k}$

The expected value of X is

MHT CET 2024 15th May Morning Shift
12

A random variable X has the following probability distribution

$X$ 1 2 3 4 5
$p(x)$ $\mathrm{k^2}$ $\mathrm{2k}$ $\mathrm{k}$ $\mathrm{2k}$ $\mathrm{5k^2}$

Then $\mathrm{p}(x \geq 2)$ is equal to

MHT CET 2024 15th May Morning Shift
13

The probability, that a year selected at random will have 53 Mondays, is

MHT CET 2024 15th May Morning Shift
14

A multiple choice examination has 5 questions. Each question has three alternative answers of which exactly one is correct. The probability that a student will get 4 or more correct answers just by guessing is

MHT CET 2024 15th May Morning Shift
15

A random variable $X$ has the following probability distribution

$X=x$ 1 2 3 4 5 6 7 8
$P(X=x)$ 0.15 0.23 0.10 0.12 0.20 0.08 0.07 0.05

For the event $E=\{X$ is a prime number $\}$, $F=\{X<4\}$, then $P(E \cup F)$ is

MHT CET 2024 11th May Evening Shift
16

Let $\mathrm{A}, \mathrm{B}$ and C be three events, which are pairwise independent and $\bar{E}$ denote the complement of an event E . If $\mathrm{P}(\mathrm{A} \cap \mathrm{B} \cap \mathrm{C})=0$ and $\mathrm{P}(\mathrm{C})>0$, then $\mathrm{P}((\overline{\mathrm{A}} \cap \overline{\mathrm{B}}) / C)$ is equal to

MHT CET 2024 11th May Evening Shift
17

A random variable x takes the values $0,1,2$, $3, \ldots$ with probability $\mathrm{P}(\mathrm{X}=x)=\mathrm{k}(x+1)\left(\frac{1}{5}\right)^x$, where k is a constant, then $\mathrm{P}(\mathrm{X}=0)$ is

MHT CET 2024 11th May Evening Shift
18

One hundred identical coins, each with probability p , of showing up heads are tossed once. If $0<\mathrm{p}<1$ and the probability of heads showing on 50 coins is equal to that of heads showing on 51 coins, then the value of $p$ is

MHT CET 2024 11th May Evening Shift
19

The p.m.f. of a random variable X is given by

$$\begin{aligned} \mathrm{P}[\mathrm{X}=x] & =\frac{\binom{5}{x}}{2^5}, \text { if } x=0,1,2,3,4,5 \\ & =0, \text { otherwise } \end{aligned}$$

Then which of the following is not correct?

MHT CET 2024 11th May Morning Shift
20

If three fair coins are tossed, then variance of number of heads obtained, is

MHT CET 2024 11th May Morning Shift
21

If $A$ and $B$ are two independent events such that $\mathrm{P}\left(\mathrm{A}^{\prime}\right)=0.75, \mathrm{P}(\mathrm{A} \cup \mathrm{B})=0.65$ and $\mathrm{P}(\mathrm{B})=\mathrm{p}$, then value of $p$ is

MHT CET 2024 11th May Morning Shift
22

The probability that a person who undergoes a bypass surgery will recover is 0.6 . the probability that of the six patients who undergo similar operations, half of them will recover is __________.

MHT CET 2024 11th May Morning Shift
23

$A$ and $B$ are independent events with $P(A)=\frac{3}{10}$, $\mathrm{P}(\mathrm{B})=\frac{2}{5}$, then $\mathrm{P}\left(\mathrm{A}^{\prime} \cup \mathrm{B}\right)$ has the value

MHT CET 2024 10th May Evening Shift
24

Minimum number of times a fair coin must be tossed, so that the probability of getting at least one head, is more than $99 \%$ is

MHT CET 2024 10th May Evening Shift
25

A random variable X assumes values $1,2,3, \ldots \ldots ., \mathrm{n}$ with equal probabilities. If $\operatorname{var}(X): E(X)=4: 1$, then $n$ is equal to

MHT CET 2024 10th May Evening Shift
26

In a game, 3 coins are tossed. A person is paid ₹ 100$, if he gets all heads or all tails; and he is supposed to pay ₹ 40 , if he gets one head or two heads. The amount he can expect to win/lose on an average per game in (₹) is

MHT CET 2024 10th May Morning Shift
27

In a Binomial distribution consisting of 5 independent trials, probabilities of exactly 1 and 2 successes are 0.4096 and 0.2048 respectively, then the probability, of getting exactly 4 successes, is

MHT CET 2024 10th May Morning Shift
28

A random variable X has the following probability distribution

$\mathrm{X}$ 1 2 3 4 5 6 7 8
$\mathrm{P(X=}x)$ 0.15 0.23 0.12 0.10 0.20 0.08 0.07 0.05

For the events $\mathrm{E}=\{\mathrm{X}$ is prime number $\}$

$$\mathrm{F}=\{\mathrm{X}<4\}$$

Then $P(E \cup F)=$

MHT CET 2024 10th May Morning Shift
29
 

There are three events $\mathrm{A}, \mathrm{B}, \mathrm{C}$, one of which must and only one can happen. The odds are 8:3 against $\mathrm{A}, 5: 2$ against B and the odds against C is $43: 17 \mathrm{k}$, then value of k is

MHT CET 2024 10th May Morning Shift
30

Four persons can hit a target correctly with probabilities $\frac{1}{2}, \frac{1}{3}, \frac{1}{4}$ and $\frac{1}{5}$ respectively. If all hit at the target independently, then the probability that the target would be hit, is

MHT CET 2024 9th May Evening Shift
31

If the mean and the variance of a Binomial variate X are 2 and 1 respectively, then the probability that X takes a value greater than one is equal to

MHT CET 2024 9th May Evening Shift
32

A bag contains 4 red and 3 black balls. One ball is drawn and then replaced in the bag and the process is repeated. Let X denote the number of times black ball is drawn in 3 draws. Assuming that at each draw each ball is equally likely to be selected, then probability distribution of $X$ is given by

MHT CET 2024 9th May Evening Shift
33

A service station manager sells gas at an average of ₹ 100 per hour on a rainy day, ₹ 150 per hour on a dubious day, ₹ 250 per hour on a fair day and ₹ $300$ on a clear sky. If weather bureau statistics show the probabilities of weather as follows, then his mathematical expectation is

Weather Clear Fair Dubious Rainy
Probability 0.50 0.30 0.15 0.05

MHT CET 2024 9th May Evening Shift
34

An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability, that the three balls have different colours, is

MHT CET 2024 9th May Morning Shift
35

A random variable X takes values $-1,0,1,2$ with probabilities $\frac{1+3 \mathrm{p}}{4}, \frac{1-\mathrm{p}}{4}, \frac{1+2 \mathrm{p}}{4}, \frac{1-4 \mathrm{p}}{4}$ respectively, where p varies over $\mathbb{R}$. Then the minimum and maximum values of the mean of X are respectively.

MHT CET 2024 9th May Morning Shift
36

If the mean and the variance of Binomial variate $X$ are 2 and 1 respectively, then the probability that X takes a value greater than or equal to one is

MHT CET 2024 9th May Morning Shift
37

If $\mathrm{P}(\mathrm{X}=2)=0.3, \mathrm{P}(\mathrm{X}=3)=0.4, \mathrm{P}(\mathrm{X}=4)=0.3$, then the variance of random variable X is

MHT CET 2024 4th May Evening Shift
38

A man and his wife appear for an interview for two posts. The probability of the husband's selection is $\frac{1}{7}$ and that of the wife's selection is $\frac{1}{5}$. If they appear for the interview independently, then the probability that only one of them is selected, is

MHT CET 2024 4th May Evening Shift
39

The expected value of the sum of the two numbers obtained on the uppermost faces, when two fair dice are rolled, is

MHT CET 2024 4th May Evening Shift
40

For an entry to a certain course, a candidate is given twenty problems to solve. If the probability that the candidate can solve any problem is $\frac{3}{7}$, then the probability that he is unable to solve at most two problem is

MHT CET 2024 4th May Evening Shift
41

A random variable has the following probability distribution

$\mathrm{X:}$ 0 1 2 3 4 5 6 7
$\mathrm{P}(x):$ 0 $\mathrm{2p}$ $\mathrm{2p}$ $\mathrm{3p}$ $\mathrm{p^2}$ $\mathrm{2p^2}$ $\mathrm{7p^2}$ $\mathrm{2p}$

Then the value of p is

MHT CET 2024 4th May Morning Shift
42

Let A and B be two events such that the probability that exactly one of them occurs is $\frac{2}{5}$ and the probability that A or B occurs is $\frac{1}{2}$, then the probability of both of them occur together is

MHT CET 2024 4th May Morning Shift
43

A random variable $X$ has the following probability distribution

$\mathrm{X:}$ 1 2 3 4 5
$\mathrm{P(X):}$ $\mathrm{k^2}$ $\mathrm{2k}$ $\mathrm{k}$ $\mathrm{2k}$ $\mathrm{5k^2}$

Then $\mathrm{P(X > 2)}$ is equal to

MHT CET 2024 4th May Morning Shift
44

A multiple choice examination has 5 questions. Each question has three alternative answers of which exactly one is correct. The probability, that a student will get 4 or more correct answers just by guessing, is

MHT CET 2024 4th May Morning Shift
45

Let a random variable X have a Binomial distribution with mean 8 and variance 4 . If $\mathrm{P}(x \leqslant 2)=\frac{\mathrm{k}}{2^{16}}$, then k is equal to

MHT CET 2024 3rd May Evening Shift
46

For the probability distribution

$\mathrm{X:}$ $-2$ $-1$ $0$ $1$ $2$ $3$
$\mathrm{p}(x):$ 0.1 0.2 0.2 0.3 0.15 0.05

Then the $\operatorname{Var}(\mathrm{X})$ is

(Given : $$\left.(0.25)^2=0.0625,(0.35)^2=0.1225,(0.45)^2=0.2025\right)$$

MHT CET 2024 3rd May Evening Shift
47

Two cards are drawn successively with replacement from a well- shuffled pack of 52 cards. Let X denote the random variable of number of kings obtained in the two drawn cards. Then $\mathrm{P}(x=1)+\mathrm{P}(x=2)$ equals

MHT CET 2024 3rd May Evening Shift
48

Two cards are drawn successively with replacement from a well shuffled pack of 52 cards. Then mean of number of kings is

MHT CET 2024 3rd May Evening Shift
49

A random variable x has the following probability distribution. Then value of $k$ is _________ and $\mathrm{P}(3< x \leq 6)$ has the value

$\mathrm{X}=x$ 0 1 2 3 4 5 6 7 8
$\mathrm{P}(x)$ $\mathrm{k}$ $\mathrm{2k}$ $\mathrm{3k}$ $\mathrm{4k}$ $\mathrm{4k}$ $\mathrm{3k}$ $\mathrm{2k}$ $\mathrm{k}$ $\mathrm{k}$

MHT CET 2024 3rd May Morning Shift
50

Let $\mathrm{X} \sim \mathrm{B}\left(6, \frac{1}{2}\right)$, then $\mathrm{P}[|x-4| \leqslant 2]$ is

MHT CET 2024 3rd May Morning Shift
51

A person throws an unbiased die. If the number shown is even, he gains an amount equal to the number shown. If the number is odd, he loses an amount equal to the number shown. Then his expectation is ₹.

MHT CET 2024 3rd May Morning Shift
52

Two cards are drawn successively with replacement from a well shuffled pack of 52 cards. Let X denote the random variable of number of jacks obtained in the two drawn cards. Then $P(X=1)+P(X=2)$ equals

MHT CET 2024 3rd May Morning Shift
53

Let in a Binomial distribution, consisting of 5 independent trials, probabilities of exactly 1 and 2 successes be 0.4096 and 0.2048 respectively. Then the probability of getting exactly 3 successes is equal to

MHT CET 2024 2nd May Evening Shift
54

The probability distribution of a random variable X is given by

$\mathrm{X=}x_i$: 0 1 2 3 4
$\mathrm{P(X=}x_i)$ : 0.4 0.3 0.1 0.1 0.1

Then the variance of X is

MHT CET 2024 2nd May Evening Shift
55

Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three persons apply for the same house is

MHT CET 2024 2nd May Evening Shift
56

A bag contains 4 Red and 6 Black balls. A ball is drawn at random from the bag, its colour is observed and this ball along with 3 additional balls of the same colour are returned to the bag. If now a ball is drawn at random from the bag, then the probability that this drawn ball is red is

MHT CET 2024 2nd May Morning Shift
57

If a discrete random variable X takes values $0,1,2,3, \ldots \ldots$. with probability $\mathrm{P}(\mathrm{X}=x)=\mathrm{k}(x+1) 5^{-x}$, where k is a constant, then $\mathrm{P}(\mathrm{X}=0)$ is

MHT CET 2024 2nd May Morning Shift
58

Ten bulbs are drawn successively, with replacement, from a lot containing $10 \%$ defective bulbs, then the probability that there is at least one defective bulb, is

MHT CET 2024 2nd May Morning Shift
59

A fair die with numbers 1 to 6 on their faces is thrown. Let $$\mathrm{X}$$ denote the number of factors of the number, on the uppermost face, then the probability distribution of $$\mathrm{X}$$ is

MHT CET 2023 14th May Evening Shift
60

The p.m.f. of a random variable $$\mathrm{X}$$ is $$\mathrm{P}(x)=\left\{\begin{array}{cl}\frac{2 x}{\mathrm{n}(\mathrm{n}+1)}, & x=1,2,3, \ldots \mathrm{n} \\ 0, & \text { otherwise }\end{array}\right.$$, then $$\mathrm{E}(\mathrm{X})$$ is

MHT CET 2023 14th May Evening Shift
61

There are 6 positive and 8 negative numbers. From these four numbers are chosen at random and multiplied. Then the probability, that the product is a negative number, is

MHT CET 2023 14th May Evening Shift
62

A lot of 100 bulbs contains 10 defective bulbs. Five bulbs are selected at random from the lot and are sent to retail store. Then the probability that the store will receive at most one defective bulb is

MHT CET 2023 14th May Evening Shift
63

Two cards are drawn successively with replacement from well shuffled pack of 52 cards, then the probability distribution of number of queens is

MHT CET 2023 14th May Morning Shift
64

For an initial screening of an entrance exam, a candidate is given fifty problems to solve. If the probability that the candidate can solve any problem is $$\frac{4}{5}$$, then the probability, that he is unable to solve less than two problems, is

MHT CET 2023 14th May Morning Shift
65

$$\text { If } f(x)= \begin{cases}3\left(1-2 x^2\right) & ; 0< x < 1 \\ 0 & ; \text { otherwise }\end{cases}$$ is a probability density function of $$\mathrm{X}$$, then $$\mathrm{P}\left(\frac{1}{4} < x < \frac{1}{3}\right)$$ is

MHT CET 2023 14th May Morning Shift
66

Three critics review a book. For the three critics the odds in favour of the book are $$2: 5, 3: 4$$ and $$4: 3$$ respectively. The probability that the majority is in favour of the book, is given by

MHT CET 2023 14th May Morning Shift
67

Two dice are rolled. If both dice have six faces numbered $$1,2,3,5,7,11$$, then the probability that the sum of the numbers on upper most face is prime, is

MHT CET 2023 13th May Evening Shift
68

A random variable $$X$$ has the probability distribution

$$X=x$$ 1 2 3 4 5 6 7 8
$$P(X=x)$$ 0.15 0.23 0.12 0.20 0.08 0.10 0.05 0.07

For the events $$E=\{X$$ is a prime number $$\}$$ and $$F=\{x<5\}, P(E U F)$$ is

MHT CET 2023 13th May Evening Shift
69

A random variable $$X$$ has the following probability distribution

$$\mathrm{X}=x$$ 0 1 2
$$\mathrm{P(X}=x)$$ $$\mathrm{4k-10k^2}$$ $$\mathrm{5k-1}$$ $$\mathrm{3k^3}$$

then P(X < 2) is

MHT CET 2023 13th May Morning Shift
70

Let $$\mathrm{X}$$ be random variable having Binomial distribution $$B(7, p)$$. If $$P[X=3]=5 P[X=4]$$, then variance of $$\mathrm{X}$$ is

MHT CET 2023 13th May Morning Shift
71

If a continuous random variable $$\mathrm{X}$$ has probability density function $$\mathrm{f}(x)$$ given by

$$f(x)=\left\{\begin{array}{cl} a x & , \text { if } 0 \leq x<1 \\ a & , \text { if } 1 \leq x<2 \\ 3 a-a x & , \text { if } 2 \leq x \leq 3 \\ 0 & , \text { otherwise } \end{array}\right.$$,

then a has the value

MHT CET 2023 13th May Morning Shift
72

A card is drawn at random from a well shuffled pack of 52 cards. The probability that it is black card or face card is

MHT CET 2023 13th May Morning Shift
73

An irregular six faced die is thrown and the probability that, in 5 throws it will give 3 even numbers is twice the probability that it will give 2 even numbers. The number of times, in 6804 sets of 5 throws, you expect to give no even number is

MHT CET 2023 12th May Evening Shift
74

A box contains 100 tickets numbered 1 to 100 . A ticket is drawn at random from the box. Then the probability, that number on the ticket is a perfect square, is

MHT CET 2023 12th May Evening Shift
75

Three fair coins with faces numbered 1 and 0 are tossed simultaneously. Then variance (X) of the probability distribution of random variable $$\mathrm{X}$$, where $$\mathrm{X}$$ is the sum of numbers on the upper most faces, is

MHT CET 2023 12th May Evening Shift
76

The p.m.f of random variate $$\mathrm{X}$$ is $$P(X)= \begin{cases}\frac{2 x}{\mathrm{n}(\mathrm{n}+1)}, & x=1,2,3, \ldots \ldots, \mathrm{n} \\ 0, & \text { otherwise }\end{cases}$$

Then $$\mathrm{E}(\mathrm{X})=$$

MHT CET 2023 12th May Morning Shift
77

An experiment succeeds twice as often as it fails. Then the probability, that in the next 6 trials there will be atleast 4 successes, is

MHT CET 2023 12th May Morning Shift
78

Two cards are drawn successively with replacement from a well shuffled pack of 52 cards. Then the probability distribution of number of jacks is

MHT CET 2023 12th May Morning Shift
79

$$\mathrm{A}$$ and $$\mathrm{B}$$ are independent events with $$\mathrm{P}(\mathrm{A})=\frac{1}{4}$$ and $$\mathrm{P}(\mathrm{A} \cup \mathrm{B})=2 \mathrm{P}(\mathrm{B})-\mathrm{P}(\mathrm{A})$$, then $$\mathrm{P}(\mathrm{B})$$ is

MHT CET 2023 12th May Morning Shift
80

Two cards are drawn successively with replacement from a well-shuffled pack of 52 cards. Then mean of number of tens is

MHT CET 2023 11th May Evening Shift
81

A fair die is tossed twice in succession. If $$\mathrm{X}$$ denotes the number of fours in two tosses, then the probability distribution of $$\mathrm{X}$$ is given by

MHT CET 2023 11th May Evening Shift
82

If $$\mathrm{A}$$ and $$\mathrm{B}$$ are two events such that $$\mathrm{P}(\mathrm{A})=\frac{1}{3}, \mathrm{P}(\mathrm{B})=\frac{1}{5}, \mathrm{P}(\mathrm{A} \cup \mathrm{B})=\frac{1}{3}$$, then the value of $$\mathrm{P}\left(\mathrm{A}^{\prime} / \mathrm{B}^{\prime}\right)+\mathrm{P}\left(\mathrm{B}^{\prime} / \mathrm{A}^{\prime}\right)$$ is

MHT CET 2023 11th May Evening Shift
83

Let a random variable $$\mathrm{X}$$ have a Binomial distribution with mean 8 and variance 4. If $$\mathrm{P}(\mathrm{X} \leq 2)=\frac{\mathrm{K}}{2^{16}}$$, then $$\mathrm{K}$$ is

MHT CET 2023 11th May Evening Shift
84

From a lot of 20 baskets, which includes 6 defective baskets, a sample of 2 baskets is drawn at random one by one without replacement. The expected value of number of defective basket is

MHT CET 2023 11th May Morning Shift
85

Three of six vertices of a regular hexagon are chosen at random. The probability that the triangle with these three vertices is equilateral, equals ___________.

MHT CET 2023 11th May Morning Shift
86

A binomial random variable $$\mathrm{X}$$ satisfies $$9. p(X=4)=p(X=2)$$ when $$n=6$$. Then $$p$$ is equal to

MHT CET 2023 11th May Morning Shift
87

The three ships namely A, B and C sail from India to Africa. If the odds in favour of the ships reaching safely are $$2: 5,3: 7$$ and $$6: 11$$ respectively, then probability of all of them arriving safely is

MHT CET 2023 10th May Evening Shift
88

If the sum of mean and variance of a Binomial Distribution is $$\frac{15}{2}$$ for 10 trials, then the variance is

MHT CET 2023 10th May Evening Shift
89

In a game, 3 coins are tossed. A person is paid ₹ 7 /-, if he gets all heads or all tails; and he is supposed to pay ₹ 3 /-, if he gets one head or two heads. The amount he can expect to win on an average per game is ₹

MHT CET 2023 10th May Evening Shift
90

A fair die is tossed twice in succession. If $$\mathrm{X}$$ denotes the number of sixes in two tosses, then the probability distribution of $$\mathrm{X}$$ is given by

MHT CET 2023 10th May Evening Shift
91

For a binomial variate $$\mathrm{X}$$ with $$\mathrm{n}=6$$ if $$P(X=4)=\frac{135}{2^{12}}$$, then its variance is

MHT CET 2023 10th May Morning Shift
92

The p.d.f. of a discrete random variable is defined as $$\mathrm{f}(x)=\left\{\begin{array}{l} \mathrm{k} x^2, 0 \leq x \leq 6 \\ 0, \text { otherwise } \end{array}\right.$$

Then the value of $$F(4)$$ (c.d.f) is

MHT CET 2023 10th May Morning Shift
93

A player tosses 2 fair coins. He wins ₹5 if 2 heads appear, ₹ 2 if one head appears and ₹ 1 if no head appears. Then the variance of his winning amount in ₹ is :

MHT CET 2023 10th May Morning Shift
94

Three critics review a book. For the three critics the odds in favor of the book are $$2: 5, 3: 4$$ and $$4: 3$$ respectively. The probability that the majority is in favor of the book, is given by

MHT CET 2023 10th May Morning Shift
95

A man takes a step forward with probability 0.4 and backwards with probability 0.6 . The probability that at the end of eleven steps, he is one step away from the starting point is

MHT CET 2023 9th May Evening Shift
96

A problem in statistics is given to three students A, B and C. Their probabilities of solving the problem are $$\frac{1}{2}, \frac{1}{3}$$ and $$\frac{1}{4}$$ respectively. If all of them try independently, then the probability, that problem is solved, is

MHT CET 2023 9th May Evening Shift
97

Two cards are drawn successively with replacement from a well shuffled pack of 52 cards, then mean of number of queens is

MHT CET 2023 9th May Evening Shift
98

In a Binomial distribution with $$\mathrm{n}=4$$, if $$2 \mathrm{P}(\mathrm{X}=3)=3 \mathrm{P}(\mathrm{X}=2)$$, then the variance is

MHT CET 2023 9th May Morning Shift
99

$$\mathrm{A}, \mathrm{B}, \mathrm{C}$$ are three events, one of which must and only one can happen. The odds in favor of $$\mathrm{A}$$ are $$4: 6$$, the odds against $$B$$ are $$7: 3$$. Thus, odds against $$\mathrm{C}$$ are

MHT CET 2023 9th May Morning Shift
100

The probability mass function of random variable X is given by

$$P[X=r]=\left\{\begin{array}{ll} \frac{{ }^n C_r}{32}, & n, r \in \mathbb{N} \\ 0, & \text { otherwise } \end{array} \text {, then } P[X \leq 2]=\right.$$

MHT CET 2023 9th May Morning Shift
101

Three fair coins numbered 1 and 0 are tossed simultaneously. Then variance Var (X) of the probability distribution of random variable $$\mathrm{X}$$, where $$\mathrm{X}$$ is the sum of numbers on the uppermost faces, is

MHT CET 2023 9th May Morning Shift
102

The incidence of occupational disease in an industry is such that the workmen have a $$10 \%$$ chance of suffering from it. The probability that out of 5 workmen, 3 or more will contract the disease is

MHT CET 2022 11th August Evening Shift
103

If $$P(A \cup B)=0.7, P(A \cap B)=0.2$$, then $$P\left(A^{\prime}\right)+P\left(B^{\prime}\right)$$ is

MHT CET 2022 11th August Evening Shift
104

Two cards are drawn successively with replacement from a well shuffled pack of 52 cards. Then mean of number of kings is

MHT CET 2022 11th August Evening Shift
105

The probability that at least one of the events $$E_1$$ and $$E_2$$ occurs is 0.6. If the simultaneous occurrence of $$\mathrm{E}_1$$ and $$\mathrm{E}_2$$ is $$0.2, \mathrm{P}\left(\mathrm{E}_1^{\prime}\right)+\mathrm{P}\left(\mathrm{E}_2^{\prime}\right)=$$

MHT CET 2021 24th September Evening Shift
106

Two dice are thrown simultaneously. If X denotes the number of sixes, then the expectation of X is

MHT CET 2021 24th September Evening Shift
107

The probability distribution of a random variable X is

$$\mathrm{X=x}$$ 1 2 3 ......... $$\mathrm{n}$$
$$\mathrm{P(X=x)}$$ $$\mathrm{\frac{1}{n}}$$ $$\mathrm{\frac{1}{n}}$$ $$\mathrm{\frac{1}{n}}$$ ......... $$\mathrm{\frac{1}{n}}$$

then Var(X) =

MHT CET 2021 24th September Evening Shift
108

A fair coin is tossed for a fixed number of times. If probability of getting 7 heads is equal to probability of getting 9 heads, then probability of getting 2 heads is

MHT CET 2021 24th September Evening Shift
109

If the probability distribution function of a random variable X is given as

$$\mathrm{X=x_i}$$ $$-2$$ $$-1$$ 0 1 2
$$\mathrm{P(X=x_i)}$$ 0.2 0.3 0.15 0.25 0.1

Then F(0) is equal to

MHT CET 2021 24th September Morning Shift
110

If $$\mathrm{P}(\mathrm{A})=\frac{3}{10}, \mathrm{P}(\mathrm{B})=\frac{2}{5}, \mathrm{P}(\mathrm{A} \cup \mathrm{B})=\frac{3}{5}$$, then $$\mathrm{P}(\mathrm{A} / \mathrm{B}) \times \mathrm{P}(\mathrm{B} / \mathrm{A})=$$

MHT CET 2021 24th September Morning Shift
111

The probability distribution of a discrete random variable X is

$$\mathrm{X}$$ 1 2 3 4 5 6
$$\mathrm{P(X)}$$ K 2K 3K 4K 5K 6K

Find the value of $$\mathrm{P}(2<\mathrm{X}<6)$$

MHT CET 2021 24th September Morning Shift
112

A die is thrown four times. The probability of getting perfect square in at least one throw is

MHT CET 2021 24th September Morning Shift
113

A man is known to speck truth 3 out of 4 times. He throws a die and reports that it is 6. Then the probability that it is actually 6 is

MHT CET 2021 23rd September Evening Shift
114

The mean of the numbers obtained on throwing a die having written 1 on three faces, 2 on two faces and 5 on one face is

MHT CET 2021 23rd September Evening Shift
115

Let two cards are drawn at random from a pack of 52 playing cards. Let X be the number of aces obtained. Then the value of E(X) is

MHT CET 2021 23rd September Evening Shift
116

A fair coin is tossed 100 times. The probability of getting a head for even number of times is

MHT CET 2021 23rd September Evening Shift
117

If the function defined by $$f(x)=K(x-x^2)$$ if $$0 < x < 1=0$$, otherwise is the p.d.f. of a r.v.X, then the value of $$P\left(X<\frac{1}{2}\right)$$ is

MHT CET 2021 23rd September Evening Shift
118

The probability distribution of the number of doublets in four throws of a pair of dice is given by

MHT CET 2021 23th September Morning Shift
119

For the probability distribution given by following

$$\mathrm{x}$$ 5 6 7 8 9 10 11
$$\mathrm{P(X=x)}$$ 0.07 0.2 0.3 $$\mathrm{k}$$ 0.07 0.04 0.02

Var(X) =

MHT CET 2021 23th September Morning Shift
120

A random variable X has the following probability distribution

$$x$$ 0 1 2 3 4 5 6 7 8
$$P(X=x)$$ K 2K 3K 4K 4K 3K 2K K K

Then $$\mathrm{P}(3<\mathrm{x} \leq 6)=$$

MHT CET 2021 23th September Morning Shift
121

Rooms in a hotel are numbered from 1 to 19. Rooms are allocated at random as guests arrive. The first guest to arrive is given a room which is a prime number. The probability that the second guest to arrive is given a room which is a prime number is

MHT CET 2021 23th September Morning Shift
122

The distribution function $$F(X)$$ of discrete random variable $$X$$ is given by

$$\mathrm{X}$$ 1 2 3 4 5 6
$$\mathrm{F (X=x)}$$ 0.2 0.37 0.48 0.62 0.85 1

Then $$\mathrm{P[X=4]+P[x=5]=}$$

MHT CET 2021 22th September Evening Shift
123

First bag contains 3 red and 5 black balls and second bag contains 6 red and 4 black balls. A ball is drawn from each bag. The probability that one ball is red and the other is black, is

MHT CET 2021 22th September Evening Shift
124

A fair coin is tossed 4 times. If $$X$$ is a random variable which indicates number of heads, then $$\mathrm{P}[\mathrm{X}<3]=$$

MHT CET 2021 22th September Evening Shift
125

If the mean and variance of a binomial distribution are 4 and 2 respectively, then probability of getting 2 heads is

MHT CET 2021 22th September Evening Shift
126

For two events $$\mathrm{A}$$ and $$\mathrm{B}, \mathrm{P}(\mathrm{A} \cup \mathrm{B})=\frac{5}{6}, \mathrm{P}(\mathrm{A})=\frac{1}{6}, \mathrm{P}(\mathrm{B})=\frac{2}{3}$$, then $$\mathrm{A}$$ and $$\mathrm{B}$$ are

MHT CET 2021 22th September Morning Shift
127

A random variable X has following distribution

$$\mathrm{X = x}$$ 1 2 3 4 5 6
$$\mathrm{P(X = x)}$$ k 3k 5k 7k 8k k

Then P (2 $$\le$$ x < 5) =

MHT CET 2021 22th September Morning Shift
128

A coin is tossed three times. If X denotes the absolute difference between the number of heads and the number of tails, then P (X = 1) =

MHT CET 2021 22th September Morning Shift
129

A random variable X $$\sim$$ B (n, p), if values of mean and variance of X are 18 and 12 respectively, then n =

MHT CET 2021 22th September Morning Shift
130

an urn contains 9 balls of which 3 are red, 4 are blue and 2 are green. Three balls are drawn at random from the urn. The probability that the three balls have difference colours is

MHT CET 2021 21th September Evening Shift
131

It is observed that $$25 \%$$ of the cases related to child labour reported to the police station are solved. If 6 new cases are reported, then the probability that at least 5 of them will be solved is

MHT CET 2021 21th September Evening Shift
132

In a meeting $$60 \%$$ of the members favour and $$40 \%$$ oppose a certain proposal. A member is selected at random and we take $$\mathrm{X}=0$$ if he opposed and $$\mathrm{X}=1$$ if he is in favour, then $$\operatorname{Var} \mathrm{X}=$$

MHT CET 2021 21th September Morning Shift
133

A lot of 100 bulbs contains 10 defective bulbs. Five bulbs selected at random from the lot and sent to retain store, then the probability that the store will receive at most one defective bulb is

MHT CET 2021 21th September Morning Shift
134

A coin is tossed and a die is thrown. The probability that the outcome will be head or a number greater than 4 or both, is

MHT CET 2021 21th September Morning Shift
135

If $$\mathrm{X}$$ is a random variable with p.m.f. as follows.

$$\begin{aligned} \mathrm{P}(\mathrm{X}=\mathrm{x}) & =\frac{5}{16}, \mathrm{x}=0,1 \\ & =\frac{\mathrm{kx}}{48}, \mathrm{x}=2, \quad \text { then } \mathrm{E}(\mathrm{x})= \\ & =\frac{1}{4}, \mathrm{x}=3 \end{aligned}$$

MHT CET 2021 21th September Morning Shift
136

The p.m.f. of a random variable X is $$\mathrm{P(X = x) = {1 \over {{2^5}}}\left( {_x^5} \right),x = 0,1,2,3,4,5}=0$$ then

MHT CET 2021 20th September Evening Shift
137

The variance of the following probability distribution is,

MHT CET 2021 20th September Evening Shift Mathematics - Probability Question 159 English

MHT CET 2021 20th September Evening Shift
138

If the sum of mean and variance of a binomial distribution for 5 trials is 1.8, then probability of a success is

MHT CET 2021 20th September Evening Shift
139

Two unbiased dice are thrown. Then the probability that neither a doublet nor a total of 10 will appear is

MHT CET 2021 20th September Evening Shift
140

Two dice are rolled simultaneously. The probability that the sum of the two numbers on the dice is a prime number, is

MHT CET 2021 20th September Morning Shift
141

A random variable X has the following probability distribution

$$\mathrm{X=x}$$ 0 1 2 3 4 5 6 7
$$\mathrm{P[X=x]}$$ 0 $$\mathrm{k}$$ $$\mathrm{2k}$$ $$\mathrm{2k}$$ $$\mathrm{3k}$$ $$\mathrm{k^2}$$ $$\mathrm{2k^2}$$ $$\mathrm{7k^2+k}$$

then F(4) =

MHT CET 2021 20th September Morning Shift
142

Rajesh has just bought a VCR from Maharashtra Electronics and the shop offers after sales service contract for Rs. 1000 for the next five years. Considering the experience of VCR users, the following distribution of maintenance expenses for the next five years is formed.

Expenses 0 500 1000 1500 2000 2500 3000
Probability 0.35 0.25 0.15 0.10 0.08 0.05 0.02

The expected value of maintenance cost is :

MHT CET 2021 20th September Morning Shift
143

If $$X \sim B(4, p)$$ and $$P(X=0)=\frac{16}{81}$$, then $$P(X=4)=$$

MHT CET 2021 20th September Morning Shift
144

The odds in favour of getting sum multiple of 3 , when pair of dice are thrown is

MHT CET 2020 19th October Evening Shift
145

If $X$ is a.r.v. with c.d.f $F(x)$ and its probability distribution is given by

$X=x$ $-1.5$ $-0.5$ 0.5 1.5 2.5
$P(X=x)$ 0.05 0.2 0.15 0.25 0.35

then, $F(1.5)-F(-0.5)=$

MHT CET 2020 19th October Evening Shift
146

The odds in favour of drawing a king from a pack of 52 playing cards is

MHT CET 2020 16th October Evening Shift
147

Out of 100 people selected at random, 10 have common cold. If five persons selected at random from the group, then the probability that at most one person will have common cold is

MHT CET 2020 16th October Evening Shift
148

The pdf of a continuous r.v. $$X$$ is given by $$f(x)=\frac{x}{8}, 0 < x < 4=0$$, otherwise, then $$P(X \leq 2)$$ is

MHT CET 2020 16th October Evening Shift
149

If a die is thrown at random, then the expectation of the number on it is

MHT CET 2020 16th October Evening Shift
150

The probability that bomb will miss the target is 0.2. Then, the probability that out of 10 bombs dropped exactly 2 will hit the target is

MHT CET 2020 16th October Morning Shift
151

The letters of the word 'LOGARITHM' are arranged at random. The probability that arrangement starts with vowel and end with consonant is

MHT CET 2020 16th October Morning Shift
152

The p.d.f of c.r.v $$X$$ is given by $$f(x)=\frac{x+2}{18}$$, if $$-2

MHT CET 2020 16th October Morning Shift
153

If the p.m.f of a. r.v. $$X$$ is given by

$$P(X=x)=\frac{{ }^5 C_x}{2^5}$$

if $$x=0,1,2, \ldots \ldots . .5=0$$,

0 , otherwise,

then which of the following is not true?

MHT CET 2020 16th October Morning Shift
154

Let $X$ be the number of successes in ' $n$ ' independent Bernoulli trials with probability of success $p=\frac{3}{4}$. The least value of ' $n$ ' so that $P(X \geq 1) \geq 0.9375$ is ......

MHT CET 2019 3rd May Morning Shift
155

The probability that three cards drawn from a pack of 52 cards, all are red is

MHT CET 2019 3rd May Morning Shift
156

$$\begin{aligned} &\text { The pdf of a random variable } X \text { is }\\ &\begin{aligned} f(x) & =3\left(1-2 x^2\right), & & 0< x<1 \\ & =0 & & \text { otherwise } \end{aligned} \end{aligned}$$

The $P\left(\frac{1}{4}< x<\frac{1}{3}\right)=\ldots$

MHT CET 2019 3rd May Morning Shift
157

A player tosses 2 fair coins. He wins Rs. 5 if 2 heads appear, Rs. 2 If 1 head appear and Rs. 1 if no head appears, then variance of his winning amount is

MHT CET 2019 3rd May Morning Shift
158

In a bionomial distribution, mean is 18 and variance is 12 then $p=$ ...........

MHT CET 2019 2nd May Evening Shift
159

The p.d.f of a random variable $x$ is given by

$$\begin{aligned} & f(x)=\frac{1}{4 a}, \quad 00) \\ & =0 \text {, otherwise } \end{aligned}$$

and $P\left(x<\frac{3 a}{2}\right)=k P\left(x>\frac{5 a}{2}\right)$ then $k=$ ..............

MHT CET 2019 2nd May Evening Shift
160

If three dices are thrown then the probability that the sum of the numbers on their uppermost faces to be atleast 5 is

MHT CET 2019 2nd May Evening Shift
161

It is observed that $25 \%$ of the cases related to child labour reported to the police station are solved. If 6 new cases are reported, then the probability that atleast 5 of them will be solved is

MHT CET 2019 2nd May Morning Shift
162

A bag contains 6 white and 4 black balls. Two balls are drawn at random. The probability that they are of the same colour is ...........

MHT CET 2019 2nd May Morning Shift
163

A random variable X has following probability distribution

$X=x$ 1 2 3 4 5 6
$P(X=x)$ K 3K 5K 7K 8K K

Then $P(2 \leq X<5)=\ldots \ldots$

MHT CET 2019 2nd May Morning Shift
164

If the c.d.f (cumulative distribution function) is given by $F(x)=\frac{x-25}{10}$, then $P(27 \leq x \leq 33)=\ldots \ldots$

MHT CET 2019 2nd May Morning Shift
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