1
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle $\mathrm{ABC}, l(\mathrm{AB})=\sqrt{23}$ units, $l(\mathrm{BC})=3$ units, $l(\mathrm{CA})=4$ units, then $\frac{\cot A+\cot C}{\cot B}$ is

A
1
B
2
C
4
D
8
2
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle ABC , with usual notations, $2 \mathrm{ac} \sin \left(\frac{\mathrm{A}-\mathrm{B}+\mathrm{C}}{2}\right)$ is equal to

A
$\mathrm{a}^2+\mathrm{b}^2-\mathrm{c}^2$
B
$\mathrm{c}^2+\mathrm{a}^2-\mathrm{b}^2$
C
$\mathrm{b}^2-\mathrm{a}^2+\mathrm{c}^2$
D
$\mathrm{a^2-b^2-c^2}$
3
MHT CET 2024 15th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle ABC , with usual notations, $\frac{\cos \mathrm{B}+\cos \mathrm{C}}{\mathrm{b}+\mathrm{c}}+\frac{\cos \mathrm{A}}{\mathrm{a}}$ has the value

A
$\frac{1}{\mathrm{~b}+\mathrm{c}}$
B
$\frac{1}{\mathrm{~b}}$
C
$\frac{1}{\mathrm{c}}$
D
$\frac{1}{\mathrm{a}}$
4
MHT CET 2024 11th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The angles of a triangle are in the ratio $5: 1: 6$, then ratio of the smallest side to the greatest side is

A
$\sqrt{3}+1: 2 \sqrt{2}$
B
$2 \sqrt{2}: \sqrt{3}+1$
C
$2 \sqrt{2}: \sqrt{3}-1$
D
$\sqrt{3}-1: 2 \sqrt{2}$
MHT CET Subjects
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