1
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+2
-0

$$ \mathop {\lim }\limits_{x \to \infty } \frac{\mathrm{e}^{x^4}-1}{\mathrm{e}^{x^4}+1}= $$

A
1
B
e
C
$\frac{1}{\mathrm{e}}$
D
not defined
2
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $f(x)= \begin{cases}\frac{8^x-4^x-2^x+1}{x^2}, & \text { if } x>0 \\ e^x \sin x+x+\lambda \log 4, & \text { if } x \leqslant 0\end{cases}$

is continuous at $x=0$ then the value of $1000 \mathrm{e}^\lambda=$

A
1000
B
3000
C
2000
D
4000 $$\mathop {\lim }\limits_{x \to {0^ - }} $$
3
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

$$ f(x)= \begin{cases}{\left[x^2\right]-\left[-x^2\right],} & x \neq 3 \\ k & , x=3\end{cases} $$

is continuous at $x=3$, then $\mathrm{k}=$ where $[\cdot]$ is greatest integer function

A
0
B
1
C
-1
D
Does not exist
4
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

$\mathop {\lim }\limits_{x \to 0} \frac{\left(7^x-1\right)^4}{\tan \left(\frac{x}{\mathrm{k}}\right) \cdot \log \left(1+\frac{x^2}{3}\right) \cdot \sin 4 x}=3(\log 7)^3$, then $\mathrm{k}=$

A
$\quad 4(\log 7)^{-1}$
B
$\frac{1}{4}(\log 7)^{-1}$
C
$\quad 4 \log \left(\frac{1}{7}\right)$
D
$\frac{1}{4} \log 7$
MHT CET Subjects
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