1
MHT CET 2021 22th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

A rectangle of maximum area is inscribed in an ellipse $$\frac{x^2}{25}+\frac{y^2}{16}=1$$, then its dimensions are

A
$$4 \sqrt{2}, 6 \sqrt{2}$$
B
$$\sqrt{2}, 5 \sqrt{2}$$
C
$$4 \sqrt{2}, 5 \sqrt{2}$$
D
$$4 \sqrt{2}, \sqrt{2}$$
2
MHT CET 2020 16th October Evening Shift
MCQ (Single Correct Answer)
+2
-0

The eccentricity of the ellipse $$y^2+4 x^2-12 x+6 y+14=0$$ is

A
$$\frac{1}{\sqrt{2}}$$
B
$$\frac{1}{2}$$
C
$$\frac{\sqrt{3}}{2}$$
D
$$\frac{1}{\sqrt{3}}$$
3
MHT CET 2019 3rd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The length of the latusrectum of an ellipse is $\frac{18}{5}$ and eccentricity is $\frac{4}{5}$, then equation of the ellipse is .....

A
$\frac{x^2}{25}+\frac{y^2}{8}=1$
B
$\frac{x^2}{25}+\frac{y^2}{9}=1$
C
$\frac{\dot{x}^2}{25}+\frac{y^2}{16}=1$
D
$\frac{x^2}{16}+\frac{y^2}{9}=1$
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