1
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $\lim\limits_{x \to 0} \dfrac{(4^x - 1)^3}{\tan\left(\dfrac{x}{4}\right)\log\left(1 + \dfrac{x^2}{3}\right)} = 96(\log a)^b$, then $(a + b) = $
A
$5$
B
$7$
C
$3$
D
$4$
2
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If the function f is continuous at $x = 1$, where $f(x) = \dfrac{1 + \cos(\pi x)}{\pi(1-x)^2}$, for $x \neq 1$, then the value of $f(1)$ is....
A
$\dfrac{\pi}{2}$
B
$\dfrac{\pi}{4}$
C
$\dfrac{\pi}{6}$
D
$\dfrac{\pi}{9}$
3
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $\quad f(x)=\left\{\begin{array}{cc}\frac{9^x-2 \cdot 3^x+1}{\log (1+3 x) \cdot \tan 2 x} & , \text { if } x \neq 0 \\ a(\log b)^c & , \text { if } x=0\end{array}\right.$ is continuous at $x=0$, then $\mathrm{a}+\mathrm{b}+\mathrm{c}=$

A

$\frac{31}{6}$

B

$\frac{1}{6}$

C

$\frac{5}{6}$

D

$\frac{3}{20}$

4
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

Define $f(x)=\left\{\begin{array}{cl}b-a x & , \text { if } x<2 \\ 3 & , \text { if } x=2 \\ a+2 b x & , \text { if } x>2\end{array}\right.$ and if $\lim _{x \rightarrow 2} f(x)$ exists, then $\frac{a}{b}=$

A

1

B

-1

C

$\frac{2}{3}$

D

$\frac{3}{2}$

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